Can someone please help thank u (. ^ ᴗ ^. )

Physics

2 answers:

Mila [183]2 years ago

8 0

Answer:

3) The answer is (b) -8 m/s (pointing down)

4) The answer is (c) -9.8 m/s^2 (acceleration of a freely falling object is always due to gravity, -9.8 m/s^2, regardless o

Explanation:

kakasveta [241]2 years ago

6 0

3) The answer is (b) -8 m/s (pointing down)

4) The answer is (c) -9.8 m/s^2 (acceleration of a freely falling object is always due to gravity, -9.8 m/s^2, regardless of direction)

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S.I unit for moment of inertia of a fly wheel

qaws [65]

Answer:

m is expressed in kilograms and r in metres, with I (moment of inertia) having the dimension kilogram-metre square.

8 0

1 year ago

Sallys physical education teacher timed her run and recorded the time and distance in the table below. What is her average speed

Fudgin [204]

Answer: B) 2.5 m/s

Explanation: Find the average of the time and distance, and see how far they go in only 1 second.

1 + 2 + 3 + 4 + 5 = 15
15 divided by 5 = 3

3 seconds

2 + 5 + 7 + 10 + 12 = 36
36 divided by 5 = 7.2

7.2m per 3 seconds.

7.2 divided by 3 = 2.4

Therefore, the answer is technically 2.4m/s

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3 years ago

Assume that the electric field E is equal to zero at a given point. Does it mean that the electric potential V must also be equa

lyudmila [28]

Answer:

No, this doesn't mean the electric potential equals zero.

Explanation:

In electrostatics, the electric field $\vec{E}$ is related to the gradient of the electric potential V with :

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r})$

This means that for constant electric potential the electric field must be zero:

$V(\vec{r}) = k$

$\vec{E} (\vec{r}) = - \vec{\nabla} V (\vec{r}) = - \vec{\nabla} k$

$\vec{E} (\vec{r}) = - (\frac{\partial}{\partial x} , \frac{\partial}{\partial y } , \frac{\partial}{\partial z}) k$

$\vec{E} (\vec{r}) = - (\frac{\partial k}{\partial x} , \frac{\partial k}{\partial y } , \frac{\partial k}{\partial z})$

$\vec{E} (\vec{r}) = - (0,0,0)$

This is not the only case in which we would find an zero electric field, as, any scalar field with gradient zero will give an zero electric field. For example:

$V(\vec{r})= (x+2)^2 (y+4)^3 (z+5)^4$