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koban [17]
2 years ago
12

Can someone please help thank u (. ^ ᴗ ^. )​

Physics
2 answers:
Mila [183]2 years ago
8 0

Answer:

3) The answer is (b) -8 m/s (pointing down)

4) The answer is (c) -9.8 m/s^2 (acceleration of a freely falling object is always due to gravity, -9.8 m/s^2, regardless o

Explanation:

kakasveta [241]2 years ago
6 0

3) The answer is (b) -8 m/s (pointing down)

4) The answer is (c) -9.8 m/s^2 (acceleration of a freely falling object is always due to gravity, -9.8 m/s^2, regardless of direction)

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A speeding Thunderbird left skid marks on the road that were 76.7 m long when it came to a stop. If the acceleration of the car
FrozenT [24]

Answer: 39.2 m/s

Explanation:

You can use the kinematic equation:

v_f^2=v_i^2+2a*d

We know the final velocity because it says it came to a stop. So now all we gotta do is plug in.

0^2=v_i^2+2(-10)(76.7)\\v_i^2=1,534\\v_i=\sqrt{1534} \\=39.166 m/s

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3 years ago
if you have a kinetic energy of 1470 J, and you are 60kg mass and 0 m above the ground, what is you velocity?
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Answer:

The 39.

Explanation:

8 0
2 years ago
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Encontrar la distancia y desplazamiento de las dos trayectorias si se mueve el móvil Desde A hasta B
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Answer:

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6 0
2 years ago
This shot is made while your body is not directly facing the basket<br><br><br> (P.E. Sub)
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2 years ago
Tina is driving her sports car down US1, traveling 27m/s. She sees her friend Rita up ahead, waiting to cross the street at the
mrs_skeptik [129]

Answer:

434 Hz

Explanation:

According to the Doppler effect, when a source of a wave is moving towards an observer at rest, then the observer will observe an apparent frequency which is higher than the original frequency of the source.

In this situation, Tina is driving towards Rita. Tina is the source of the sound wave (the horn), while RIta is the observer. Since the original frequency of the sound is 400 Hz, Rita will hear a sound with a frequency higher than this value.

The only choice which is higher than 400 Hz is 434 Hz, so this is the frequency that Rita will hear.

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