Explanation:
a. the total time taken for the journey is 50sec.
b. u=0, v=10m/sec, t=20sec.
a=(v-u)/t = (10-0)/20 = 10/20 = 0.5 m/s².
hope this helps you to solve the problem.
The I3 will be 158 A.
<h3>How to find the current through the circuit?</h3>
- The foundation of circuit analysis is Kirchhoff's circuit laws.
- We have the fundamental instrument to begin studying circuits with the use of these principles and the equation for each individual component (resistor, capacitor, and inductor).
- These rules aid in calculating the current flow in various network streams as well as the electrical resistance of a complicated network, or impedance in the case of AC.
To calculate I3 firstly, V4 has to be calculated,
![V_{4} =I_{4} R_{4}](https://tex.z-dn.net/?f=V_%7B4%7D%20%3DI_%7B4%7D%20R_%7B4%7D)
![V_{4} = V_{2} / R_{4} + R_{5} * R_{4}](https://tex.z-dn.net/?f=V_%7B4%7D%20%3D%20V_%7B2%7D%20%2F%20R_%7B4%7D%20%2B%20R_%7B5%7D%20%20%2A%20R_%7B4%7D)
![V_{4} = 12 * 135 / 135+61](https://tex.z-dn.net/?f=V_%7B4%7D%20%3D%2012%20%2A%20135%20%2F%20135%2B61)
![V_{4} = 8.26V](https://tex.z-dn.net/?f=V_%7B4%7D%20%3D%208.26V)
For I3,
![I_{3} = R_{1} /(R1+R3 + (R1+R3)(R2+R6) * (V2 - V1 (R1+R2+R6/R1)](https://tex.z-dn.net/?f=I_%7B3%7D%20%3D%20R_%7B1%7D%20%2F%28R1%2BR3%20%2B%20%28R1%2BR3%29%28R2%2BR6%29%20%2A%20%28V2%20-%20V1%20%28R1%2BR2%2BR6%2FR1%29)
![I3=(61)/((61)(50)+(61+50)(141+141)) (12 -18 (1+(141+141)/61)) = -.158 A](https://tex.z-dn.net/?f=I3%3D%2861%29%2F%28%2861%29%2850%29%2B%2861%2B50%29%28141%2B141%29%29%20%2812%20-18%20%281%2B%28141%2B141%29%2F61%29%29%20%3D%20-.158%20A)
Hence, the current through I3 will be 158 A.
To learn more about Kirchoff's laws refer to:
brainly.com/question/86531
#SPJ 10
Answer:
This is so confusing I tried solving but didn't understand it
Answer:
![F_{net}=N\ sin\theta](https://tex.z-dn.net/?f=F_%7Bnet%7D%3DN%5C%20sin%5Ctheta)
Explanation:
Let a car of m is on an incline bank of angle θ and it is rounding a curve with no friction. We need to find the centripetal force acting on it.
The attached free body diagram shows the car on the banked turn. It is clear that,
In vertical direction,
![N\ cos\theta=mg](https://tex.z-dn.net/?f=N%5C%20cos%5Ctheta%3Dmg)
In horizontal direction,
![F_{net}=F_{centripetal}](https://tex.z-dn.net/?f=F_%7Bnet%7D%3DF_%7Bcentripetal%7D)
![F_{net}=N\ sin\theta](https://tex.z-dn.net/?f=F_%7Bnet%7D%3DN%5C%20sin%5Ctheta)
So, the centripetal force is equal to
. Hence, the correct option is (c).