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Answer:
2022 L
Explanation:
Ideal gas laws will work for gas in the balloon
The general gas law is for a gas at two arbitrary states 1 and 2 is given by
(P₁ V₁)/T₁ = (P₂ V₂)/T₂
P₁ = 1.17 atm
V₁ = 200.0 L
T₁ = 20°C = 293.15 K
P₂ = 63 mmHg = 0.0829 atm
V₂ = ?
T₂ = 210 K
(1.17 × 200)/293.15 = (0.0829 × V₂)/210
V₂ = (210 × 1.17 × 200)/(293.15 × 0.0829)
V₂ = 2022 L
A) Magnesium + Chlorine -> Magnesium chloride ( Mg + Cl2 -> MgCl2)
b) Potassium + Oxygen -> Potassium oxide
( 2K + O2 -> K2O )
c) Sodium + Bromine -> Sodium bromide
( 2Na + Br2 -> 2NaBr)
d) Carbon + Oxygen -> Carbon dioxide
( C + O2 -> CO2 ) This reaction occurs when heated.
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Since the forward reaction is endothermic (heat is consumed in the reaction) that means that the enthalpy change for the forward reaction is a positive value.
Therefore, i would say that the reverse or backward reaction is exothermic (heat is released in the reaction to the sorroundings) and that the enthalpy change is a negative value.
