Answer:
The percentage of the simulations of two games that the football player would most likely get a touchdown in each of the two games = 15.21%
Step-by-step explanation:
The probability of scoring a touchdown in one game for the football player = 39% = 0.39
Probability of scoring a touchdown in each of the two consecutive games = (Probability of scoring a touchdown in the first game) × (Probability of scoring a touchdown in the second game)
Since the probability of scoring a touchdown in each game the football player plays in is independent of one another.
Probability of scoring a touchdown in the first game = Probability of scoring a touchdown in the second game = 0.39
Probability of scoring a touchdown in each of the two consecutive games = 0.39 × 0.39 = 0.1521
If 100 simulations of the two games are made, the player scores in each of the two games in 15.21 of them, hence, the percentage of the simulations that the football player would most likely get a touchdown in each of the two games = 15.21%
Hope this Helps!!
The answer would be7,500,000
31. +
34. -
To figure out more, just solve the known problem, and then go over what the answer would be to the unknown one until you find the answer that makes it true.
Answer:
b
Step-by-step explanation:
if a is perp to b, and b is parallel to c, and c is parallel to d, then a is perp to d
