Convert 15/2 to a mixed fraction

Khloe and Emma work at a furniture store. Khloe is paid $245 per week plus 9.5% of her total sales in dollars, xx, which can be

ale4655 [162]

Answer: Their weekly pay would be the same if xx equals $1,600

Step-by-step explanation: The first and most important step is to identify what the question requires, and that is, what is the value of the unknown in the equation of their weekly incomes that would make their pay to be the same? Their weekly pay as per individual is given as follows;

Khloe = 245 + 0.095x ———(1)

Emma = 285 + 0.07x ———(2)

Simply put, we need to find the value of x when equation (1) equals equation (2)

245 + 0.095x = 285 + 0.07x

Collect like terms and we now have

0.095x - 0.07x = 285 - 245

0.025x = 40

Divide both sides of the equation by 0.025

x = 1600

Therefore their weekly pay would be at the same level, if x equals $1600

6 0

3 years ago

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the

Darya [45]

Answer:

Brand 1 Brand 2 Difference

37734 35202 2532

45299 41635 3664

36240 35500 740

32100 31950 150

37210 38015 −805

48360 47800 560

38200 37810 390

33500 33215 285

Sum of difference = 2532+ 3664+740+150 −805+ 560 +390 +285 = 7516

Mean = $d=\frac{7516}{8}$

Mean = $d=939.5$

a) d= 939.5

$\text{Sample Standard deviation, s} = \sqrt{\dfrac{(x-\bar{x})^2}{n-1}}$

$=\sqrt{\dfrac{(2532-939.5)^2+(3664-939.5)^2+(740-939.5)^2 ...+(285-939.5)^2}{8-1}}$

=1441.21

b)SD= 1441.21

c)Calculate a 99% two-sided confidence interval on the difference in mean life.

confidence level =99%

significance level =α= 0.01

Degree of freedom = n-1 = 8-1 =7

So, $t_{\frac{\alpha}{2}}=3.499$

Formula for confidence interval $= \left( \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}} \right)$

Substitute the values

confidence interval $= 939.5 \pm 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

confidence interval $= 939.5 - 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$ to $= 939.5 + 3.499 \times \frac{1441.21}{\sqrt{8}} \right)$

Confidence interval $−843.396\$ to $2722.396$

8 0

3 years ago

The sum of two numbers is 18. The larger number is twice as large as the smaller number. What are the two numbers? Please explai

snow_tiger [21]

The two numbers are 12 and 16. 12 + 6 = 18. 6 doubled is 12. 12 plus 6 equals 18.

7 0

3 years ago

PLZ HELP ME!<br> Directions up above the picture<br> **MATH (Algebra)

Vikentia [17]

Answer:

The answer to your question is t = 1.3 s

Step-by-step explanation:

Data

Equation h(t) = -4.9t² + v₀t + h₀

v₀ = 0 m/s

h₀ = 8 m

t = ?

h = 0 m

Process

1.- Substitute the values in the formula

0 = -4.9t² + 0t + 8

2.- Simplification

0 = -4.9t² + 8

3.- Solve for t

4.9t² = 8

t² = 8/4.9

t² = 1.63

4.- Result

t = 1.27 ≈ 1.3 s

6 0

3 years ago

I’m need this worked out step by step by tonight

Pie

9514 1404 393

Answer:

-3 ≤ x ≤ 19/3

Step-by-step explanation:

This inequality can be resolved to a compound inequality:

-7 ≤ (3x -5)/2 ≤ 7

Multiply all parts by 2.

-14 ≤ 3x -5 ≤ 14

Add 5 to all parts.

-9 ≤ 3x ≤ 19

Divide all parts by 3.

-3 ≤ x ≤ 19/3

_____

<em>Additional comment</em>

If you subtract 7 from both sides of the given inequality, it becomes ...

|(3x -5)/2| -7 ≤ 0

Then you're looking for the values of x that bound the region where the graph is below the x-axis. Those are shown in the attachment. For graphing purposes, I find this comparison to zero works well.

__

For an algebraic solution, I like the compound inequality method shown above. That only works well when the inequality is of the form ...

|f(x)| < (some number) . . . . or ≤

If the inequality symbol points away from the absolute value expression, or if the (some number) expression involves the variable, then it is probably better to write the inequality in two parts with appropriate domain specifications:

|f(x)| > g(x) ⇒ f(x) > g(x) for f(x) > 0; or -f(x) > g(x) for f(x) < 0

Any solutions to these inequalities must respect their domains.

8 0

3 years ago