Convert 15/2 to a mixed fraction

Which equation is related to this equation? b + 17 = 52

Neporo4naja [7]

It would be d because you would subtract 52 from 17 to get the answer then add the number you got to 17 to get 52.

7 0

3 years ago

Read 2 more answers

Tell me please I need help with this one guys pleaseee thanks you so much :()))

siniylev [52]

A. At the very end
B.one more away from that
C.on the left

7 0

3 years ago

Find the volume of the given solid. Under the surface z = 6xy and above the triangle with vertices (1, 1), (4, 1), and (1, 2)

Leya [2.2K]

he volume of the solid under a surface

z

=

f

(

x

,

y

)

and above a region D is given by the formula

∫

D

f

(

x

,

y

)

d

A

.

Here

f

(

x

,

y

)

=

6

x

y

. The inequalities that define the region D can be found by making a sketch of the triangle that lies in the

x

y

−

plane. The bounding equations of the triangle are found using the point-slope formula as

x

=

1

,

y

=

1

and

y

=

−

x

3

+

7

3

.

Here is a sketch of the triangle:

Intersecting Region

The inequalities that describe D are given by the sketch as:

1

≤

x

≤

4

and

1

≤

y

≤

−

x

3

+

7

3

.

Therefore, volume is

V

=

∫

4

1

∫

−

x

3

+

7

3

1

6

x

y

d

y

d

x

=

∫

4

1

6

x

[

y

2

]

−

x

3

+

7

3

1

d

x

=

3

∫

4

1

x

[

y

2

]

−

x

3

+

7

3

1

d

x

=

3

∫

4

1

x

[

49

9

−

14

x

9

+

x

2

9

−

1

]

d

x

=

3

∫

4

1

40

x

9

−

14

x

2

9

+

x

3

9

d

x

=

3

[

40

x

2

18

−

14

x

3

27

+

x

4

36

]

4

1

=

3

[

(

640

18

−

896

27

+

256

36

)

−

(

40

18

−

14

27

+

1

36

)

]

=

23.25

.

Volume is

23.25

.

4 0

3 years ago

In the 1990s the demand for personal computers in the home went up with household income. For a given community in the 1990s, th

WITCHER [35]

Answer:

a) 0.5198 computers per household

b) 0.01153 computers

Step-by-step explanation:

Given:

number of computers in a home,

q = 0.3458 ln x - 3.045 ; 10,000 ≤ x ≤ 125,000

here x is mean household income

mean income = $30,000

increasing rate, $\frac{dx}{dt}$ = $1,000

Now,

a) computers per household are

since,

mean income of $30,000 lies in the range of 10,000 ≤ x ≤ 125,000

thus,

q = 0.3458 ln(30,000) - 3.045

or

q = 0.5198 computers per household

b) Rate of increase in computers i.e $\frac{dq}{dt}$

$\frac{dq}{dt}$ = $\frac{d(0.3458 ln x - 3.045)}{dt}$

or

$\frac{dq}{dt}=0.3458\times(\frac{1}{x})\frac{dx}{dt} - 0$

on substituting the values, we get

$\frac{dq}{dt}=0.3458\times(\frac{1}{30,000})\times1,000$

or

= 0.01153 computers

6 0

3 years ago

81,27,9,__,__,__,__ fill in the blanks

Sever21 [200]

3, 1, 0.3333, 0.111111
I think

5 0

3 years ago