Question

what is the solubility of ca(oh)2 (s) in water, given that the ksp is 6.5 x 10-6. molar mass of ca(oh)2 is 74.09 g/mol. g

Answer 1

8.7M  Is the solubility of Ca(oh)2  in water at a given Ksp of 6.5 .10-6  and molar mass of   74.09g/mol.

Solubility is defined as the amount of the substance  dissolved in a given amount of solvent at a certain temperature.

Ca(OH)2   à  Ca2+  +  2OH-

Ksp = 6.5 .10-6

Molar mass= 74.09 g/mol

Ksp is solubility product constant which describes the equilibrium between a solid and its ion in solution.

          Ksp=[Ca2+] [OH2-]

      6.5 .10-6 = S. (74.09g/mol +S)

      6.5 .10-6 = S .( 74.09M)

        S = 6.5 .10-6 /74.09 M

            =  8.7 M

       So, the solubility of Ca(OH)2  is  8.7M.

To learn more about solubility product constant please visit:

brainly.com/question/1419865

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