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Julli [10]
1 year ago
13

what is the solubility of ca(oh)2 (s) in water, given that the ksp is 6.5 x 10-6. molar mass of ca(oh)2 is 74.09 g/mol. g

Chemistry
1 answer:
Pani-rosa [81]1 year ago
8 0

8.7M  Is the solubility of Ca(oh)2  in water at a given Ksp of 6.5 .10-6  and molar mass of   74.09g/mol.

Solubility is defined as the amount of the substance  dissolved in a given amount of solvent at a certain temperature.

Ca(OH)2   à  Ca2+  +  2OH-

Ksp = 6.5 .10-6

Molar mass= 74.09 g/mol

Ksp is solubility product constant which describes the equilibrium between a solid and its ion in solution.

          Ksp=[Ca2+] [OH2-]

      6.5 .10-6 = S. (74.09g/mol +S)

      6.5 .10-6 = S .( 74.09M)

        S = 6.5 .10-6 /74.09 M

            =  8.7 M

       So, the solubility of Ca(OH)2  is  8.7M.

To learn more about solubility product constant please visit:

brainly.com/question/1419865

#SPJ4

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5 0
3 years ago
The decomposition of dinitrogen pentaoxide has an activation energy of 102 kj/mol and \delta ? h°rxn = + 55 kj/mol. what is the
posledela
A positive cahnge of enthalpy, ΔH rxn = + 55 kJ/mol, for the forward reaction means that the reaction is endothermic, i.e. the reactants absorb energy and the products are higher in energy.

Activation energy is the difference in the energy level of the reactants and the peak in the potential energy diagram (the energy of the transition state).

For an endothermic reaction, the products will be closer in energy to the transition state than what the reactans will be; so, the activation energy of the reversed reaction is lower than the activation energy of the forward reaction.

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Answer: 47 kJ/mol
8 0
3 years ago
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