8.7M Is the solubility of Ca(oh)2 in water at a given Ksp of 6.5 .10-6 and molar mass of 74.09g/mol.
Solubility is defined as the amount of the substance dissolved in a given amount of solvent at a certain temperature.
Ca(OH)2 à Ca2+ + 2OH-
Ksp = 6.5 .10-6
Molar mass= 74.09 g/mol
Ksp is solubility product constant which describes the equilibrium between a solid and its ion in solution.
Ksp=[Ca2+] [OH2-]
6.5 .10-6 = S. (74.09g/mol +S)
6.5 .10-6 = S .( 74.09M)
S = 6.5 .10-6 /74.09 M
= 8.7 M
So, the solubility of Ca(OH)2 is 8.7M.
To learn more about solubility product constant please visit:
brainly.com/question/1419865
#SPJ4
