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Arte-miy333 [17]
3 years ago
13

.-. spooooooooooooooooooooooooooooooooooooooooooooooooooopy ok

Physics
1 answer:
Whitepunk [10]3 years ago
6 0

Answer:

omggghshsbsnznxjdbdn

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A 2.0 kg stone is tied to a 0.50 m string and swung around a circle at a constant angular velocity of 12 rad/s. The circle is pa
Paul [167]

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The magnitude of the torque about the origin is 108 N-m.

Explanation:

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The circle is parallel to the xy plane and is centered on the z axis, 0.75 m from the origin, r = 0.75 m

Firstly it is required to find the centripetal force acting on the stone. It is given by :

F=mr\omega^2

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