Answer:
what?
Explanation:
write it correctly I don't understand the question
<span>Satellite in a circular orbit of radius r around planet x has an orbital period t. if planet x had one-fourth as much mass, the orbital period of this satellite in an orbit of the same radius would be 2t</span>
After the foot leaves the ball, the acceleration is always downward and is equal to g at all points
Answer:
The magnitude of the torque about the origin is 108 N-m.
Explanation:
Given that,
Mass of the stone, m = 2 kg
Length of the string, l = 0.5 m
Angular velocity of the stone, 
The circle is parallel to the xy plane and is centered on the z axis, 0.75 m from the origin, r = 0.75 m
Firstly it is required to find the centripetal force acting on the stone. It is given by :


F = 144 N
Now the magnitude of the torque about the origin is given by :



So, the magnitude of the torque about the origin is 108 N-m. Hence, this is the required solution.