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dimulka [17.4K]
3 years ago
7

When waves superimpose and make bigger amplitudes what form of interference is that

Physics
1 answer:
eimsori [14]3 years ago
7 0

Answer:

Constructive Interference

Explanation:

Constructive Interference occurs when two waves superimpose and make bigger amplitudes.

In constructive interference, the crests of one wave fall on the crests of second wave and the amplitudes add up. The amplitude of the resultant wave is equal to sum of the amplitude of the individual waves. Similarly, the trough of first wave falls on the trough of other wave and they superimpose to create the trough of the resultant wave.

For Example, In the attachment, two waves A and B superimpose and demonstrate Constructive interference to create the wave C.

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<span>The sprinter is advised to reduce his speed slowly after completing the race because of the power that is needed when the stoppage is down in a faster manner could be very great. This would translate to the great usage in gasoline. Also, the inertia of the vehicle is quiet high so it is hard to stop it very suddenly. </span>

5 0
3 years ago
1. A Passenger car (m= 10.0 kg) and a flat car (m= 7.5 kg) collide and move off as
grin007 [14]

Answer:

use a calculator to solve that

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Near the center of our galaxy, hydrogen gas is moving directly away from us in its orbit about a black hole. The electromagnetic
klemol [59]

To solve this problem it is necessary to apply the concept related to wavelength, specifically when the wavelength is observed from a source that is in motion to the observer.

By definition the wavelength is given defined by,

\lambda_{obs} = \lambda_s \sqrt{\frac{1+u/c}{1-u/c}}

Where

\lambda_{obs} = Observed wavelength

\lambda_s = Wavelength of the source

c = Speed of light in vacuum

u = Relative velocity of the source to the observer

According to our data we have that the wavelength emitted from the galaxy is 1875nm which is equal to the wavelength from the source, while the wavelength from the observer is \lambda_{obs}=1945nm

Therefore replacing in the previous equation we have,

1945 = 1875 \sqrt{\frac{1+\frac{u}{c} }{1-\frac{u}{c} }}

\sqrt{\frac{1+u/c}{1-u/c}} = 1.03733

\frac{1+\frac{u}{c} }{1-\frac{u}{c} }=1.03733^2

1+\frac{u}{c} =1.03733^2*(1-\frac{u}{c} )

Solving for u,

1+\frac{u}{c} =1.03733^2*(1-\frac{u}{c} )

1+\frac{u}{c} =1.03733^2-1.03733^2(\frac{u}{c} )

\frac{u}{c} +1.03733^2\frac{u}{c} =1.03733^2-1

2.88595\frac{u}{c}=1.03733^2-1

\frac{u}{c} = \frac{1.03733^2-1}{2.88595}

u = \frac{1.03733^2-1}{2.88595}*c

u = 0.02635c

Therefore the speed of the gas relative to earth is 0.02635 times the speed of light.

6 0
3 years ago
A cup of water is warmed from 21 °C to 85 °C. What is the difference between these two temperatures, in kelvins?
Ilya [14]

Answer:

337k

Explanation:

First, let us find the difference between the given two temperatures.

Difference = 85°C - 21°C

                  = 64°C

<u>And now we have to write the temperature in kelvins.</u>

To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.

<u>Let us find it now.</u>

64°C + 273 = 337k

Therefore,

64°C ⇒ <u>337k</u>

8 0
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Why does a balloon stick to a wall questions and problems answers?
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