How do you find the uncertainty of a meter stick?
Thus, L =5 . 7 cm measured with a meter stick implies an uncertainty of 0.05 cm. A common rule of thumb is to take one-half the unit of the last decimal place in a measurement to obtain the uncertainty
Answer:
s=4.44 m
Explanation:
Given that
Coefficient of the kinetic friction ,μ = 0.13
Initial velocity ,u= 3.4 m/s
Final velocity of the box ,v= 0 m/s
The acceleration due to friction force
a= - μ g
Now by putting the values in the above equation
a= - 0.13 x 10 ( take g= 10 m/s²)
a= - 1.3 m/s²
We know that
v²= u ² + 2 a s
s=distance
a=acceleration
v=final speed
u=initial speed
Now by putting the values in the above equation
0²= 3.4² - 2 x 1.3 x s

s=4.44 m
The distance cover by box will be 4.44 m.
Answer:
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<h2>Answer:</h2>
Acceleration= -1.11 m/sec²
<h2>Explanation:</h2>
Date Given to us is
Mass = 150 kg
Time = 1.5 minutes = 90 seconds
Distance = 2500 meters
Initial Velocity = 120 m/s
Final Velocity = 20 m/s
Acceleration = ?
<u>Solution:</u>
By using First Equation of motion
Vf = Vi + at
Putting the values
20 = 120 + a (90)
Subtracting 120 on both sides
20-120 = 120 + a(90) - 120
-100 = 90 a
Dividing both sides by 90
-100/90 = 90 a / 90
-1.11 = a
So the acceleration is -1.11 m/s²
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