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Ad libitum [116K]
3 years ago
15

What type of element is phosphorus

Chemistry
2 answers:
Snezhnost [94]3 years ago
6 0
I think the answer is non metal
mrs_skeptik [129]3 years ago
5 0

The answer is <u><em>non-metal.</em></u>

<h3>Here's why:</h3>

The element Phosphorus is located on the <em>right </em>side of the periodic table, where the majority of the non and semi metals are.


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The difference in hydrogen ion concentration between solutions with ph4 and ph5 is
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When lewis structures are drawn, do you only show valence electrons??
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Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m
Bond [772]

Answer:

m_{H_2O}=4.86gH_2O

Explanation:

Hello,

In this case, the described chemical reaction is:

C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O

Best regards.

3 0
3 years ago
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I'm pretty sure its momentum

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A meteor is moving 468 km per minute traveling in a south-to-north direction passed near Earth in 2013. Does this statement desc
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Answer:

it's describes the velocity. since a direction was specifically given, that means it is displacement, and displacement is to velocity while distance is to speed

3 0
3 years ago
Read 2 more answers
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