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3 years ago

What type of element is phosphorus

Chemistry

2 answers:

Snezhnost [94]3 years ago

6 0

I think the answer is non metal

mrs_skeptik [129]3 years ago

5 0

The answer is non-metal.

The element Phosphorus is located on the right side of the periodic table, where the majority of the non and semi metals are.

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What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of 0.35 atm and water vapor at a par

Fofino [41]

According to Dalton's Law, in a mixture of non-reacting gasses, thetotal pressure exerted is the sum of the partial pressures of the component gasses. In more complicated circumstances, equilibrium states come into effect, but fortunately for us, oxygen is non-reactive with water vapor.

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3 years ago

2. what is nappening in this diagram:

natka813 [3]

Answer:

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2 years ago

Tin metal reacts with hydrogen fluoride to produce tin (ll )fluoride and hydrogen gas according to the balanced equation. Sn(s)+

ladessa [460]

Answer:

1.263 moles of HF

Explanation:

The balance chemical equation for given single replacement reaction is;

Sn + 2 HF → SnF₂ + H₂

Step 1: Calculate Moles of Tin as;

As we know,

Moles = Mass / A.Mass ----- (1)

Where;

Mass of Tin = 75.0 g

A.Mass of Tin = 118.71 g/mol

Putting values in eq. 1;

Moles = 75.0 g / 118.71 g/mol

Moles = 0.6318 moles of Sn

Step 2: Find out moles of Hydrogen Fluoride as;

According to balance chemical equation,

1 mole of Sn reacted with = 2 moles of HF

So,

0.6318 moles of Sn will react with = X moles of HF

Solving for X,

X = 0.6318 mol × 2 mol / 1 mol

X = 1.263 moles of HF

8 0

2 years ago

If 62.3 mL of lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.862 g of precipitate, wh

Alexxx [7]

Answer:

The molarity of the lead(II) ion in the original solution is 0.03M

Explanation:

Step 1: The balanced reaction

Pb(NO3)2(aq) + 2 NaI aq) → PbI2(s) + 2 NaNO3 (aq)

Pb2+ + 2I- →PbI2

This means that for 1 mole Pb2+ consumed, there is needed 2 moles of I- to produce 1 mole of PbI2

Step 2: Calculate moles of PbI2

Moles of PbI2 = 0.862g / 461.01 g/mole

moles of PbI2 = 0.00187 moles

Step 3: calculate moles of Pb2+

For 1 mole of PbI2 produced we need 1 mole of Pb2+

This means for 0.00187 moles of PbI2 we need 0.00187 moles of Pb2+

Step 4: Calculate the molarity of the Pb2+ ion

Molarity of Pb2+ = moles of Pb2+ / volume =

Molarity of Pb2+ = 0.00187 moles / 62.3*10^-3

Molarity of Pb2+ ion = 0.03M

The molarity of the lead(II) ion in the original solution is 0.03M

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3 years ago

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Marrrta [24]

Answer:

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3 years ago

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