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a_sh-v [17]
3 years ago
13

You accelerate a 0.43kg football 5m/s2. Calculate the force you applied to the football.

Physics
1 answer:
Elza [17]3 years ago
7 0

The force applied on the football is 2.15 Newton.

Given the data in the question;

  • Mass of football; m = 0.43kg
  • Acceleration; a = 5m/s^2

Force applied; F = \ ?

To determine the force applied on the football, we use Newton's laws of motion:

F = m * a

Where m is the mass of the object and a is the acceleration.

We substitute our given values into the equation

F = 0.43kg\ *\ 5m/s^2\\\\F = 2.15kg.m/s^2\\\\F = 2.15N

Therefore, the force applied on the football is 2.15 Newton.

Learn more: brainly.com/question/2388393

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Answer:

Final temperature, T2 = 314.9 Kelvin

Explanation:

Given the following data:

Mass = 0.9kg

Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K

Quantity of heat = 120,000 J

Specific heat capacity = 4182 j/kgK

To find the final temperature;

Heat capacity is given by the formula;

Q = mcdt

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

Making dt the subject of formula, we have;

dt = \frac {Q}{mc}

Substituting into the equation, we have;

dt = \frac {120000}{0.9*4182}

dt = \frac {120000}{3763.8}

dt = 31.9K

Now, the final temperature T2 is;

But, dt = T2 - T1

T2 = dt + T1

T2 = 31.9 + 283

T2 = 314.9 Kelvin

8 0
3 years ago
What was the voltage on the battery for the #2 series circuit with two light bulbs?A: 4 VB: 18 VC: 4.5 VD: 9 V
Ghella [55]

We are given a series circuit with two light bulbs. In this case, the light bulbs act as resistors in series and the total resistance is:

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Where "R" is the total resistance and "I" is the current in the circuit. Replacing we get:

V=I(R_1+R_2)

8 0
1 year ago
After robbing a bank, a criminal tries to escape from the police by driving at a constant speed of 55 m/s (about 125 mph). A pol
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Answer:

18.03 s

Explanation:

We have two different types of motions, the criminal moves with uniform motion while the police do it with uniformly accelerated motion. Therefore we will use the equations of these cases. We know that by the time the police reach the criminal they will have traveled the same distance.

x=vt\\x=x_{0}+v_{0}t+\frac{a}{2}t^2

The distance between the police and the criminal when the first one starts the persecution is 0, its initial speed is also zero. So:

x=(55m/s)t\\x=\frac{6.1m/s^2}{2}t^2=(3.05m/s^2)t^2

Equalizing these two equations and solving for t:

(55m/s)t=(3.05m/s^2)t^2\\(3.05m/s^2)t^2-(55m/s)t=0\\t((3.05m/s^2)t-55m/s)=0\\t=0 \\(3.05m/s^2)t-55m/s=0\\t=\frac{55m/s}{3.05m/s^2}=18.03 s

6 0
3 years ago
A woman using a compass and a map walks 132 east of north for 6 km
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If she walks 132 and 6 you do 132 x 6 = 792
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3 years ago
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Proved that<br>V = u+at<br>​
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Answer:

\sf Proof \ below

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Solve for v.

Multiply both sides by t.

\sf at=v-u

Add u to both sides.

\sf at + u=v

3 0
3 years ago
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