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Tpy6a [65]
3 years ago
12

What is the mass of 0.850 mole of SO2?

Chemistry
2 answers:
Hunter-Best [27]3 years ago
8 0

Answer :

The answer is 54.4 grams

Vesnalui [34]3 years ago
6 0

Answer:

1 \: mole \: of \: sulphurdioxide \: weighs \: 64 \: g \\ 0.850 \: moles \: will \: weigh \: (0.850 \times 64) \: g \\  = 544 \: g

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How many moles is 2.55 x 10 to the power of 26 atoms of Neon?​
Yakvenalex [24]

Answer:

424 mol

Explanation:

Step 1: Given data

Number of atoms of Neon: 2.55 × 10²⁶ atoms

Step 2: Calculate the number of moles corresponding to 2.55 × 10²⁶ atoms of Neon

In order to convert atoms into moles, we need a conversion factor, which is Avogadro's number: there are 6.02 × 10²³ atoms of Neon in 1 mole of atoms of Neon.

2.55 × 10²⁶ atoms × (1 mol/6.02 × 10²³ atoms) = 424 mol

4 0
3 years ago
Suppose you have just added 200.0 ml of a solution containing 0.5000 moles of acetic acid per liter to 100.0 ml of 0.5000 M NaOH
uranmaximum [27]

Answer:

The final pH is 3.80

Explanation:

Step 1: Data given

Volume of acetic acid = 200.0 mL = 0.200 L

Number of moles acetic acid = 0.5000 moles

Volume of NaOH = 100.0 mL = 0.100 L

Molarity of NaOH = 0.500 M

Ka of acetic acid = 1.770 * 10^-5

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa + H2O

Step 3: Calculate moles

moles = molarity * volume

Moles NaOH = 0.500 M * 0.100 L

Moles NaOH = 0.0500 moles

Step 4: Calculate the limiting reactant

For 1 mol CH3COOH we need 1 mol NaOH to produce 1 mol CH3COONa and 2 moles H2O

NaOH is the limiting reactant. It will completely be consumed (0.0500 moles). CH3COOH is in excess. There will react 0.0500 moles . There will remain 0.500 - 0.0500 = 0.450 moles

There will be produced 0.0500 moles CH3COONa

Step 5: Calculate the total volume

Total volume = 200.0 mL + 100.0 mL = 300.0 mL

Total volume = 0.300 L

Step 6: Calculate molarity

Molarity = moles / volume

[CH3COOH] = 0.450 moles / 0.300 L

[CH3COOH] = 1.5 M

[CH3COONa] = 0.0500 moles / 0.300 L

[CH3COONa]= 0.167 M

Step 7: Calculate pH

pH = pKa + log[A-]/ [HA]

pH = -log(1.77*10^-5) + log (0.167/ 1.5)

pH = 4.75 + log (0.167/1.5)

pH = 3.80

The final pH is 3.80

7 0
3 years ago
HELP ASAP!! PLZ
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D. The empirical formula and the molar mass

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2 years ago
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Exothermic  releases energy(heat) from the system to the surrounding
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Cutting the cardboard would be the first step
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