The answer is D all of the above because I just got done with this question
Answer:
15.3 g
Explanation:
- Fe₂O₃ (s) + 2Al (s) → 3Fe (l) + Al₂O₃ (s)
First we convert 8.0 grams of aluminum into moles, using its molar mass:
- 8.0 g Al ÷ 27 g/mol = 0.30 mol Al
Then we <u>convert 0.30 moles of aluminum into moles of aluminum oxide</u>, using the<em> stoichiometric coefficients</em>:
- 0.30 mol Al * = 0.15 mol Al₂O₃
Finally we convert 0.15 moles of Al₂O₃ into grams, using its molar mass:
- 0.15 mol Al₂O₃ * 102 g/mol = 15.3 g Al₂O₃
The correct answer is B.Condensation. The other person who answered this question is wrong, it is NOT A. precipitation.
Answer:
74 g/mol
Explanation:
Using a periodic table, we can determine the molar mass by adding together 1 Ca, 2 O, and 2 H. This turns out to be approximately (40+32+2) = 74 g/mol