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Thepotemich [5.8K]
3 years ago
8

The sound wave produced from playing the A key one octave above the "Middle C" on the plano produces a sound wave with a frequen

cy of 880 Hz. The speed of sound moving through the air at room temperature is 344 m/s. What is the wavelength of the sound waves associated with the A key?
Physics
2 answers:
Vaselesa [24]3 years ago
4 0

Answer: well I think you have to take 800 Hz x 344 m/s Which should equal around 275200 ;-; and then divide it by something (I did this once but I cant remember the rest .-.)

natita [175]3 years ago
3 0

Answer:

<u>Frequency</u>- number of wave cycles that occur in a given amount of time.

<u>Pitch</u>- number of wavelengths in a given amount of time.

<u>Amplitude</u>- fluctuation or displacement of a wave from its mean value. That means how high or low they are away from the center line.

<u>Volume</u>- The perception of loudness from the intensity of a sound wave. The higher the intensity of a sound, the louder it is perceived in our ears, and the higher volume it has.

<u>Wavelength</u>- the distance between the tops of the "waves".

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Answer:

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Explanation:

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Dado que V₁ = V₂  (el volumen del neumático no cambia), al introducir la ecuación (1) en la ecuación (2) podemos encontrar la presión final:

P_{2} = \frac{nRT_{2}}{V_{2}} = \frac{nRT_{2}}{\frac{nRT_{1}}{P_{1}}} = \frac{P_{1}T_{2}}{T_{1}} = \frac{1.5 atm*(67 + 273)K}{300 K} = 1.7 atm  

Por lo tanto, si en el transcurso de un viaje las ruedas alcanzan una temperatura de 67 ºC, el neumático soportará una presión de 1.7 atm.

Espero que te sea de utilidad!

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