For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

here weight will act at mid point of door so its distance is half of the total distance where force is applied
here we know that

now we will have


so our applied force is 72.5 N
Where is the rest .........
Answer:
The new kinetic energy would be 16 times greater than before.
Explanation:
Kinetic energy is found using this formula:
- KE = 1/2mv²
- where KE = kinetic energy (J), m = mass (kg), and v = velocity (m/s)
We can see that kinetic energy is directly proportional to the square of the velocity, meaning that if the speed was increased by 4 times, then the kinetic energy would get increased by a factor of 16.
The velocity just before the ball hits the ground can be found by the equation:
Let's substitute h = 10 m and h = 40 m into this formula.
We can see that the velocity increases by a factor of 4 (10 m → 40 m).
Therefore, this means that the kinetic energy would also be increased by a factor of (4)² = 16. Thus, the answer is D) The new kinetic energy would be 16 times greater than before.
To solve this problem, we will apply the concepts related to the linear deformation of a body given by the relationship between the load applied over a given length, acting by the corresponding area unit and the modulus of elasticity. The mathematical representation of this is given as:

Where,
P = Axial Load
l = Gage length
A = Cross-sectional Area
E = Modulus of Elasticity
Our values are given as,
l = 3.5m
D = 0.028m

E = 200GPa

Replacing we have,




Therefore the change in length is 1.93mm