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Morgarella [4.7K]
3 years ago
13

Question 3 of 10

Physics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

8 m/s

Explanation:

KE Formula: KE = 1/2mv^2

Kinetic Energy is equal to energy, J.

6400 = 1/2 * 200 * V^2

1/2 * 200 = 100

6400 = 100 * V^2

6400/100 =  V^2

64 = V^2

Square root both sides

Speed is  8 m/s

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Refraction occurs when light passing from one medium to another. True or False
kodGreya [7K]

Answer: True

Refraction is a phenomenon in which the light bends or changes its direction (and changes the speed of propagation, as well) <u>when passing through a medium</u> with a refractive index n <u>different from the other medium.  </u>

Where the Refractive index is a number that describes how fast light propagates through a medium or material:

n=\frac{c}{v}

Being n a relation between the speed of light in vacuum c  and its speed in the other medium v .

It is important to note that in this process, the wavelength may be modified because it depends on the medium, however, the refracted ray of light does not change its frequency.

7 0
4 years ago
Suggest two uses of pulleys.
Marizza181 [45]

Answer: Elevators use pulleys to function.

A cargo lift system that allows for items to be hoisted to higher floors is a pulley system.

Explanation:

8 0
3 years ago
The barometer of a mountain hiker reads 930 mbars at the beginning of a hiking trip and 780 mbars at the end. Neglecting the eff
lara31 [8.8K]
We could use the change of pressure to calculate for the height climbed by the mountain hiker. The change of pressure is given by

p = rho * g * h, where p is the change of pressure, rho is the air density, g is the acceleration due to gravity, and h is the height.

Using the conversion 1 mbar = 100 Pa,

(930 - 780)(100) = (1.20)(9.80)h
15000 = 1.20*9.80*h

h = 1.28 km
6 0
4 years ago
What are the differences between forces and pressure​
slamgirl [31]

Answer:

Force is a push or pull action between objects. Pressure is force acting on a surface area of an object, thus it is force per unit area.

Explanation:

4 0
3 years ago
A bicyclist of mass 60kg supplies 340W of power while riding into a 5 m/s head wind. The frontal area of the cyclist and bicycle
NikAS [45]

Answer:

87.1 mph

Explanation:

We are given that

Mass,m=60 kg

Power,P=340 W

Speed,v=5 m/s

Area,A=0.344 m^2

Drag coefficient,C_d=0.88

Coefficient of rolling resistance,\mu_r=0.007

Friction force,f=\mu_rmg=0.007\times 60\times 9.8=4.1 N

Where g=9.8 m/s^2

Let speed of cyclist=v'

Drag force,F_d=\frac{1}{2}\rho_{air}AC_dv^2

Density of air,\rho_{air}=1.225 kg/m^3

F_d=\frac{1}{2}\times 1.225\times 0.344\times 0.88(5)^2=4.635N

Power,P=(F_d+f)\times v'

340=(4.1+4.635) v'=8.735v'

v'=\frac{340}{8.735}=38.9m/s

v'=87.1 mph

1 m=0.00062137 miles

1 hour=3600 s

7 0
4 years ago
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