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Morgarella [4.7K]
3 years ago
13

Question 3 of 10

Physics
1 answer:
KonstantinChe [14]3 years ago
8 0

Answer:

8 m/s

Explanation:

KE Formula: KE = 1/2mv^2

Kinetic Energy is equal to energy, J.

6400 = 1/2 * 200 * V^2

1/2 * 200 = 100

6400 = 100 * V^2

6400/100 =  V^2

64 = V^2

Square root both sides

Speed is  8 m/s

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When a dielectric material is inserted between two plates of capacitor that are connected to a battery, you would observe that both the charge and the capacitance of the capacitor would change. This is due to the dielectric material which is able to transmit electric force.
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Light waves travel through space
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C.even though there is almost no material in the interstellar medium, but do transfer  energy.

Explanation:

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7 0
3 years ago
How many times larger than a centigram is a dekagram
Umnica [9.8K]

Answer:

A dekagram is thousand (1000) times larger than a centigram.

Explanation:

→ [1 dekagram = 1,000 centigrams]

→ 1 dekagram = 10 grams

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3 0
3 years ago
Low-pressure areas tend to ____ before occluding and ____ after occluding
alexgriva [62]

Out of the following given choices;

a. decelerate; accelerate

b. accelerate; decelerate

c. stop; accelerate

d. decelerate; stop

<span>The answer is B.  This is because the cold front usually rotates around the warm front as cold air mass coverage in the low-pressure system. This causes the cold air mass to accelerate to catch up with the warm front. When an occluded front ( that is the boundary that separates the older cool air mass already in place from new incoming cold air mass), that the system decelerates. </span>






4 0
4 years ago
At what speed must a 950-kg subcompact car be moving to have the same kinetic energy as a 3.2×104−kg truck going 20 km/h?
Ostrovityanka [42]

<u>Answer:</u>

 950-kg subcompact car be moving to have the same kinetic energy of truck at 116.08 km/hr

<u>Explanation:</u>

  Kinetic energy of body with mass m and moving at velocity v is given by

                  KE=\frac{1}{2} mv^2

  KE of truck  = \frac{1}{2}*3.2*10^4*20^2

  KE of subcompact car = \frac{1}{2}*950*v^2

  Equating

         \frac{1}{2}*3.2*10^4*20^2= \frac{1}{2}*950*v^2\\ \\ v=116.08 km/hr

 So 950-kg subcompact car be moving to have the same kinetic energy of truck at 116.08 km/hr

6 0
4 years ago
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