Answer:
The materials with which the lab group are to use for the model includes;
i) A candle
ii) A match
iii) A strip of cloth
iv) Tongs
v) A metal can
The processes the lab group are to model are;
a) Conduction
b) Convection
c) Radiation
The procedure the lab group can use to do this is outlined as follows;
1) Tie the piece of cloth around the metal can with a strip of the cloth extending past the bottom of the can
2) Hold the metal can in with the aid of the tongs
3) Light the candle with the match
4) Place the metal can over over the burning candle so that it does not touch the flame
5) While holding the can with the tongs, ensure that the strip of cloth hanging by the side of the can does not come in contact with the flame
Conduction
Conduction heat transfer is observed by the rising temperature of the tongs that is in the contact with the can
Convection
Convection heat transfer is observed by the rising temperature of the can that is placed in the path of the rising convection current from the candle wax
Radiation
Radiation heat transfer is observed by the shrinking of the piece of cloth placed beside the candle flame
Explanation:
Left. Use right hand rule. Have hand wide open. Thumb points in direction of current.(which makes right angle with your index finger) Four fingers in direction of magnetic field and your palm should point in the direction of the force
Answer:
0.0003 m = 0.3 mm
Explanation:
For constructive interference in the Young's experiment.
The position of the mth fringe from the central fringe is given by
y = L(mλ/d)
λ = wavelength = 720 nm = 720 × 10⁻⁹ m
L = distance between slits and screen respectively = 1.0 m
d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m
m = 2
y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm
For the 620 nm light,
y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm
Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m
Answer:
The impulse transferred to the nail is 0.01 kg*m/s.
Explanation:
The impulse (J) transferred to the nail can be found using the following equation:
Where:
: is the final momentum
: is the initial momentum
The initial momentum is given by:
Where 1 is for the hammer and 2 is for the nail.
Since the hammer is moving down (in the negative direction):
And because the nail is not moving:
Now, the final momentum can be found taking into account that the hammer remains in contact with the nail during and after the blow:
Since the hammer and the nail are moving in the negative direction:
= 
= -9.7 m/s
Finally, the impulse is:
Therefore, the impulse transferred to the nail is 0.01 kg*m/s.
I hope it helps you!
