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erastovalidia [21]
3 years ago
10

Amelia is doing an experiment in which she is

Physics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

tie hair back

only burn the amount of chemicals as

directed by the lab procedure

Explanation:

The correct safety precautions for Amelia to take from the options would be <u>to tie her hair back</u> and t<u>o only burn the amount of chemicals recommended by the lab procedure.</u>

<em>With her hair left flowing freely, Amelia runs the risk of the hair catching flame while trying to burn the chemicals according to the procedure. Hence, tying her hair up into one neat bunch will limit the risk of it catching fire while working in the lab.</em>

<em>Also, burning less or more than the amount of chemicals recommended by the procedure may be dangerous or hinder Amelia from getting the right result.</em>

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How does earths magnetic field protect us from solar flares
Alex787 [66]

Answer:

Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

4 0
2 years ago
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(b) The density of aluminum is 2.70 g/cm3. The thickness of a rectangular sheet of aluminum foil varies
vekshin1

Answer:

(i) 22.48 cm^3

(ii) 1.5 mm

Explanation:

Let t be the average thickness of the sheet.

Given that:

Density of the aluminum sheet is 2.70 g/cm^3

Mass of sheet = 60.7 g

Length of sheet  = 50.0 cm

Width of sheet  = 30.0 cm

(i) Using, Density=Mass/Volume

\Rightarrow \text{Volume}=\frac{\text{Mass}}{\text{Density}}

\Rightarrow \text{Volume}=\frac{60.7}{2.7}=22.48 cm^3

Hence, the volume of the sheet is 22.48 cm^3.

(ii) Now, as this aluminum sheet is in the shape of a cuboid, so the volume of the sheet is

\text{Volume}=\text{Length}\times\text{Width}\times\text{Thickness}

\Rightarrow 22.48=50\times 30 \times w

\Rightarrow w=\frac{22.48}{50\times 30}=0.015 cm

Hence, the average thickness of the sheet is 1.5 mm.

6 0
4 years ago
Where would you expect to find extrusive igneous rock?
Masja [62]
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4 years ago
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How to do this, i'm completely lost
vaieri [72.5K]
There are two torques t1 and t2 on the beam due to the weights, one torque t3 due to the weight of the beam, and one torque t4 due to the string.

You need to figure out t4 to know the tension in the string.

Since the whole thing is not moving t1 + t2 + t3 = t4.

torque t = r * F * sinФ = distance from axis of rotation * force * sin (∡ between r and F)

t1 =3.2 * 44g 
t2 = 7 * 49g 
t3 = 3.5 * 24g 

t4 = t1 + t2 + t3 = 5570,118

The t4 also is given by:

t4 = r * T * sin Ф

r = 7
Ф = 32°
T: tension in the string

T = t4 / (r * sinФ)

T = t4 / (7 * sin(32°)) 

T = 1501,6 N

8 0
4 years ago
If a loaded truck that accelerates at 1 meter per second squared loses its load and has three-fourths of the origional mass, wha
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I believe it'd accelerate at 1.25 m/s^2 instead of 1, as it lost 1/4 of its mass (.25), so now it is .25 of 1 faster.

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