Hello There!
<em>If you add together all of the forces exerted on a object and get a non zero value that is called the "NET FORCE" of the object</em>
The concept required to solve this problem is quantization of charge.
First the number of electrons will be calculated and then the total mass of the charge.
With these data it will be possible to calculate the percentage of load in the mass.

Here Q is the charge, n is the number of electrons and e is the charge on the electron

Replacing,


According to the quantization of charge the charge is defined as product of the number of electron and the charge on the electron
The total mass of the charge is

Here,
m = Mass of the charge
n = Number of electrons
= Mass of the electron

Replacing we have


<em>★</em><em> </em><em>«</em><em> </em><em><u>what is sound wave and examples</u></em><em><u> </u></em><em>»</em><em> </em><em>★</em>
- <em>A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.</em>
<em>hope </em><em>it</em><em> helps</em>
Answer:
The voltage on the secondary is 12 V while the current is 0.5 A.
Explanation:
A transformer works by changing the level of the voltage and current on a circuit using a magnetic field and two coils. The ratio by wich they are changed is dependant on the ratio of turns between the primary and secondary of the transformer. In this case we have a ratio for the voltage of:
ratio = (turns on the secondary)/(turns on the primary)
ratio = 100/1000 = 0.1
So in this case the voltage delivered to the primary will be multiplied by 0.1. We can now calculate the voltage on the secondary:
Voltage secondary = Voltage primary* ratio = 120*0.1 = 12 V
The transformer maintains roughly the same power output on both sides, since the power output on a electric circuit is given by the product of the voltage by the current on that circuit, to maintain the same power when the voltage has been droped the current must be raised by the same ratio. So we have:
Current secondary = Current primary*(1/ratio) =0.05*(1/0.1) = 0.5 A