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sertanlavr [38]
3 years ago
5

Simplify fully X squared - 8x + 15 Over X squared + x -12

Mathematics
2 answers:
Likurg_2 [28]3 years ago
4 0
\frac{x^2-8x+15}{x^2+x-12}=\frac{x^2-3x-5x+15}{x^2-3x+4x-12}=\frac{x(x-3)-5(x-3)}{x(x-3)+4(x-3)}=\frac{(x-5)(x-3)}{(x+4)(x-3)}= \\
=\boxed{\frac{x-5}{x+4}}, x \not= -4 \hbox{ and } x\not= 3
zimovet [89]3 years ago
3 0
\frac{x^{2} - 8x + 15}{x^{2} + x - 12} = \frac{x^{2} - 5x - 3x + 15}{x^{2} + 4x - 3x - 12} = \frac{(x - 3)(x - 5)}{(x - 3)(x + 4)} = \frac{x - 5}{x + 4}
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Answer:

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\begin{center}\begin{tabular}{ c c c }Hours(h) & Total Cost(C) \\ 1 & 15  \\  2 & 20  \\   3 & 25  \\ 4 & 30   \\ 5 & 35    \end{tabular}\end{center}

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