Answer:
The answer is 11 electron and 11 protons respectively
Explanation:
Since the sodium is in it neutral state, number of electron is the same as the number of proton, which is 11.
Complete question:
ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.
Answer:
The magnitude of q for the process 568 J.
Explanation:
Given;
change in internal energy of the gas, ΔU = 475 J
work done by the gas, w = 93 J
heat added to the system, = q
During gas expansion process, heat is added to the gas.
Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.
ΔU = q - w
q = ΔU + w
q = 475 J + 93 J
q = 568 J
Therefore, the magnitude of q for the process 568 J.
Answer:
A. Sublimation of camphor
Explanation:
A clastic sedimentary rock is a rock that is formed from pre-existing rock materials and minerals. This materials have been transported to their new positions by the agents of denudation.
- Clastic sedimentary rocks are made up of rock fragments predominantly.
- The matrix is usually remnants of other rocks.
- A cementing material can form between clasts and holds them in place. Cements are usually iron oxides, calcite e.t.c.
- These rock types are usually formed from mechanincal weathering of rocks
- Mechanical weathering breaks down rocks into chunks.
- Examples are breccia, conglomerates, e.t.c.
Learn more:
Sedimentary rocks brainly.com/question/2740663
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