Answer:
Explanation:
the solution to the problem is given in the pictures attached. (b) is answered first then (a). I hope the explanation helps you.Thank you
The probability that the player gets doubles less than three times in 5 attempts is; 0.9645.
<h3>How to solve Binomial Probability?</h3>
The formula for binomial probability distribution is;
P(X = x) = ⁿCₓ × pˣ × (1 - p)⁽ⁿ ⁻ ˣ⁾
where;
x = total number of successes
p = probability of a success on an individual trial
n = number of trials
We are given;
x = 3
p = 1/6 = 0.1667
n = 5
Thus;
P(X < 3) = (⁵C₂ * 0.1667 * (1 - 0.1667)⁽⁵ ⁻ ²⁾) + (⁵C₁ * 0.1667 * (1 - 0.1667)⁽⁵ ⁻ ¹⁾) + (⁵C₀ * 0.1667 * (1 - 0.1667)⁽⁵ ⁻ ⁰⁾)
Thus;
P(X < 3) = 0.9645
Thus, the probability that the player gets doubles less than three times in 5 attempts is 0.9645.
Read more about Binomial Probaility at; brainly.com/question/15246027
Answer:
I have attached the diagram for this question below. Consult it for better understanding.
Find the cross sectional area AB:
A = (1.6mm)(12mm) = 19.2 mm² = 19.2 × 10⁻⁶m
Forces is given by:
F = 2.75 × 10³ N
Horizontal Stress can be found by:
σ (x) = F/A
σ (x) = 2.75 × 10³ / 19.2 × 10⁻⁶m
σ (x) = 143.23 × 10⁶ Pa
Horizontal Strain can be found by:
ε (x) = σ (x)/ E
ε (x) = 143.23 × 10⁶ / 200 × 10⁹
ε (x) = 716.15 × 10⁻⁶
Find Vertical Strain:
ε (y) = -v · ε (y)
ε (y) = -(0.3)(716.15 × 10⁻⁶)
ε (y) = -214.84 × 10⁻⁶
<h3>PART (a)</h3>
For L = 0.05m
Change (x) = L · ε (x)
Change (x) = 35.808 × 10⁻⁶m
<h3>
PART (b)</h3>
For W = 0.012m
Change (y) = W · ε (y)
Change (y) = -2.5781 × 10⁻⁶m
<h3>PART(c)</h3>
For t= 0.0016m
Change (z) = t · ε (z)
where
ε (z) = ε (y) ,so
Change (z) = t · ε (y)
Change (z) = -343.74 × 10⁻⁹m
<h3>
PART (d)</h3>
A = A(final) - A(initial)
A = -8.25 × 10⁻⁹m²
(Consult second picture given below for understanding how to calculate area)