Hydrogen gas (density = 1.165 kg/m^3 ) is stored at 25°C in a permeable cylindrical container which has an outer diameter of 0.2
5 m, a wall thickness of 5 mm and a length of 2 m. The cylinder is exposed to ambient air.
If the container is charged to an initial pressure of 5 bars, at what would be the mass diffusion rate (in kg/s) of hydrogen through the cylinder? Hydrogen solubility in the container is 0.5X10^(-3) kmol/m^3 bar and diffusivity at 293K and 1 bar is 0.4x10^(-13) m^2 /s.
If the container is charged to an initial pressure of 5 bars, at what would be the mass diffusion rate (in kg/s) of hydrogen through the cylinder? Hydrogen solubility in the container is 0.5X10^(-3) kmol/m^3 bar and diffusivity at 293K and 1 bar is 0.4x10^(-13) m^2 /s.
1 answer:
You might be interested in
- Computer systems organization.
- Computing methodologies.
- General and reference.
- Networks.
- Software and its engineering.
- Theory of computation.
Answer:
Go to explaination for the details of the answer.
Explanation:
In order to determine the lifetime (75 years) chronic daily exposure for each individual, we have to first state the terms of our equation:
CDI = Chronic Daily Intake
C= Chemical concentration
CR= Contact Rate
EFD= Exposure Frequency and Distribution
BW= Body Weight
AT = Average Time.
Having names our variables lets create the equations that will be used to derive our answers.
Please kindly check attachment for details of the answer.
Answer:
The pressure reduces to 2.588 bars.
Explanation:
According to Bernoulli's theorem for ideal flow we have
Since the losses are neglected thus applying this theorm between upper and lower porion we have
Now by continuity equation we have
Applying the values in the Bernoulli's equation we get
Answer:
b) false
Explanation:
We know that Otto cycle is the ideal cycle for all petrol working engine.In Otto cycle all process are consider is ideal ,means there is no any ir-reversibility in the processes.
It consist four processes
1-2:Reversible adiabatic compression
2-3:Constant volume heat addition
3-4:Reversible adiabatic expansion
3-4:Constant volume heat rejection
Along with above 4 processes intake and exhaust processes are parallel to each other.From the P-v diagram we can see that all processes.
But actually in general we are not showing intake and exhaust line then it did not mean that in Otto cycle did not have intake and exhaust processes.
