Answer : The concentration of 
 is, 0.12 M
Explanation :
Using Henry's law :

where,
 = concentration of 
 = ?
 = partial pressure of 
 = 4.5 atm
 = Henry's law constant  = 
Now put all the given values in the above formula, we get:


Thus, the concentration of 
 is, 0.12 M
 
        
             
        
        
        
Answer:
A) The effect on the net reaction catalyzed by glyceraldehyde is that 
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be  no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived 
C ) Arsenate is very toxic to most organisms and it is used mostly regarded  as poisons during the formation of glycolysis, it forms  1-arsen0, 3-phosphoglycerate which  hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells 
Explanation:
A) The effect on the net reaction catalyzed by glyceraldehyde is that 
The 1-arsen0, 3-phosphoglycerate will decompose without enzymes hence no ATP will be formed in the reaction ( phosphoglycerate Kinase )
B) There will be  no conversion of ADP to ATP from the conversion of glucose to pyruvate hence No balanced overall equation can be derived 
C ) Arsenate is very toxic to most organisms and it is mostly regarded as  poisons during the formation of glycolysis, it forms  1-arsen0, 3-phosphoglycerate which  hinders the formation of ATP because it is unstable and will hydrolyze quickly, this will also lead to the reduction in oxygen in cells thereby leading to the death of cells 
 
        
             
        
        
        
Answer:
the are coefficients for the atom. the tell how many there are. 
Explanation:
they tell you how many atoms there are of its type.
ex. 4 C²H³. there are 4 of the c² and h³ (couldn't find a way to use subscript so used the power signs to show.)
 
        
             
        
        
        
The mole fraction of a gaseous compound is equal to the ratio of the vapor pressure of the compound to the total pressure of the vessel. In this case, teh vapor pressure of tehe non-electrolyte is 760 - 745 = 15 mmHg. hence the mole fraction is 15 mm Hg / 760 mmHg equal to 0.0197