Question

Back to 'Energy & Work'

Answer 1

Answer:

Explanation: Two possible solutions

in the absence of friction

mgh = ½mv²

h = v²/2g = 24.4²(2(9.81) = 30.344...  = 30.3 m

if enough rolling friction exists to keep the ball from sliding, but ignoring air resistance and assuming the ball is already rolling smoothly at the start

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½((2/3)mR²)(v/R)²

2gh = v² + (2/3)v²

2gh = (5/3)v²

h = (5/6)v²/g

h = (5/6)24.4²/9.81 = 50.5742 = 50.6 m