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3 years ago

Back to 'Energy & Work'

Physics

1 answer:

mixer [17]3 years ago

3 0

Answer:

Explanation: Two possible solutions

in the absence of friction

mgh = ½mv²

h = v²/2g = 24.4²(2(9.81) = 30.344... = 30.3 m

if enough rolling friction exists to keep the ball from sliding, but ignoring air resistance and assuming the ball is already rolling smoothly at the start

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½((2/3)mR²)(v/R)²

2gh = v² + (2/3)v²

2gh = (5/3)v²

h = (5/6)v²/g

h = (5/6)24.4²/9.81 = 50.5742 = 50.6 m

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To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a ho

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This question is incomplete, the missing image is uploaded along this answer.

Answer:

the coefficient of friction is 0.32

Explanation:

Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

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Fc = mrω²

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f = Fc

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2 years ago

The route followed by a hiker consists of three displacement vectors A with arrow, B with arrow, and C with arrow. Vector A with

Zarrin [17]

Answer:

B= 5,655 m C= 5,890 m.

Explanation:

We are told that the hiker ended up back where she started, so the total displacement was 0.

As displacement is a vector, if the magnitude is 0, this means that their components, along any axis must be 0 too.

If we choose the W-E direction as our x axis (with origin in the start and end point of the travel), being the E direction the positive, and we do the same with the N-S direction (we make it our y axis, with N as positive), we can write the following:

Δx = Δy=0

Next, we sum all the components of A, B and C along x axis, based on the question premises, as follows:

Δx = 1,230 m* cos 36º + B*sin 41º - C*cos 37º =0 (1)

Δy = 1,230 m*sin 36º -B*cos 41º + C* sin 37º = 0

We have a system of 2 linear equations with 2 unknowns (B and C) which can be solved by any suitable method: substitution, sum and substraction, determinants, etc).

Using determinants, we find first the determinant of the unknowns, as follows:

Δ = sin 41º*sin 37º - (-(cos 37º)*(-cos 41º) = -0.208

Now we find the numerator in order to get the value of B, replacing the B column by the independent terms'column:

ΔB = -1230*cos 36º*sin 37º - (-1230*sin 36º*(-cos 37º) = -1,177

⇒ B = ΔB / Δ = -1,177/-0.208 = 5,655 m

Repeating the same process, we get the value for ΔC, as follows:

ΔC = -1230*sin 36º*sin 41º - (-1230*cos 36º*(-cos 41º)) = -1,225

⇒ C = ΔC / Δ = -1,225/-0.208 = 5,890 m

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