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2 years ago

9

Back to 'Energy & Work'

1 answer:

mixer [17]2 years ago

3 0

Answer:

Explanation: Two possible solutions

in the absence of friction

mgh = ½mv²

h = v²/2g = 24.4²(2(9.81) = 30.344... = 30.3 m

if enough rolling friction exists to keep the ball from sliding, but ignoring air resistance and assuming the ball is already rolling smoothly at the start

mgh = ½mv² + ½Iω²

mgh = ½mv² + ½((2/3)mR²)(v/R)²

2gh = v² + (2/3)v²

2gh = (5/3)v²

h = (5/6)v²/g

h = (5/6)24.4²/9.81 = 50.5742 = 50.6 m

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(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a

GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

The distance to go between airports A and C is 373.6 10³ m

The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

R = Ra x² + y²

R = 10³

R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

v = $\frac{\Delta y }{t}$

t = $\frac{\Delta y}{v}$

They ask for the time in in from airport A to B, we calculate

t = 360 10 ^ 3/170

t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

The distance to go between airports A and C B is 373.6 10³ m

The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

5 0

2 years ago

0.A 20-g bullet moving at 1 000 m/s is fired through a one-kg block of wood emerging at a speed of 100 m/s. What is the kinetic

Fiesta28 [93]

Answer:

KE = 0.162 KJ

Explanation:

given,

mass of bullet (m)= 20 g = 0.02 Kg

speed of the bullet (u)= 1000 m/s

mass of block(M) = 1 Kg

velocity of bullet after collision (v)= 100 m/s

kinetic energy = ?

using conservation of momentum

m u = m v + M V

0.02 x 1000 = 0.02 x 100 + 1 x V

20 = 2 + V

V = 18 m/s

now,

Kinetic energy of the block

$KE = \dfrac{1}{2}mv^2$

$KE = \dfrac{1}{2}\times 1 \times 18^2$

KE = 162 J

KE = 0.162 KJ

4 0

2 years ago

What effects do oceans have on climate? A. Ocean winds bring rain and fog and often bring warm water that keeps the climate mild

nalin [4]

A. Ocean winds bring rain and fog and often bring warm water that keeps the climate mild

7 0

2 years ago

A constant magnetic field passes through a single rectangular loop whose dimensions are 0.42 m x 0.54 m. The magnetic field has

olga_2 [115]

Answer:

$0.29887\ \text{V}$

Explanation:

A = Area = $0.42\times0.54\ \text{m}^2$

B = Magnetic field = 1.7 T

$\theta$ = Angle that magnetic field makes with the plane of the loop = $71^{\circ}$

t = Time = 0.42 s

EMF is given by

$\varepsilon=A\cos\theta\dfrac{dB}{dt}\\ =\dfrac{0.42\times 0.54\times\cos 71^{\circ}\times 1.7}{0.42}\\ =0.29887\ \text{V}$

The magnitude of the average emf induced in the loop is $0.29887\ \text{V}$ .

8 0

2 years ago

What is the frequency of a sound wave having a velocity of 341 meters/second and a wavelength of 0.8 meters?

ololo11 [35]

Velocity=frequency/wavelength
frequency=velocity*<span>wavelength
</span>f=341*0.8
f=272.8 Hz

7 0

3 years ago