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Salsk061 [2.6K]
3 years ago
9

A train is traveling at a speed of 80\,\dfrac{\text{km}}{\text{h}}80 h km ​ 80, start fraction, start text, k, m, end text, divi

ded by, start text, h, end text, end fraction when the conductor applies the brakes. The train slows with a constant acceleration of magnitude 0.5\,\dfrac{\text{m}}{\text{s}^2}0.5 s 2 m ​ 0, point, 5, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. We want to find the distance the train travels from the time the conductor applies the brakes until the train comes to a complete stop. Which kinematic formula would be most useful to solve for the target unknown? Choose 1 answer:
Physics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer:

The distance the train travels before coming to a (complete) stop = 40/81 km which is approximately 493.83 meters

Explanation:

The initial speed of the train u = 80 km/h = 22 2/9 m/s = 22.\bar 2 m/s

The magnitude of the constant acceleration with which the train slows, a = 0.5 m/s²

Therefore, we have the following suitable kinematic equation of motion;

v² = u² - 2 × a × s

Where;

v = The final velocity = 0 (The train comes to a stop)

s = The distance the train travels before coming to a stop

Substituting the  values gives;

0² = 22.\bar 2² - 2 × 0.5 × s

2 × 0.5 × s = 22.\bar 2²

s = 22.\bar 2²/1 = 493 67/81 m = 40/81 km

The distance the train travels before coming to a (complete) stop = 40/81 km ≈ 493.83 m.

otez555 [7]3 years ago
4 0

Answer:

v^2=v0^2+2aΔx

Explanation:

cuz khan academy says so

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c

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A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 780 N on him. The
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3 years ago
A 0.54 kg air hockey puck is initially at rest. What will it's kinetic energy energy be after a net force of 0.56 N acts on it f
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Kf = 470 mJ

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       W_{net} = F_{net} * \Delta X = 0.56 N * 0.84 m = 0.47 J = 470 mJ (1)

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Two forces F1 and F2 are acting on a block of mass m=1.5 kg. The magnitude of
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Explanation:

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