Answer:
Explanation:
Maximum speed is get at maximum power. Let assume that ship travels at constant speed, the expression for power is equal to:
Where and
are the forward force and speed of ship measured in newtons and meters per second, respectively.
The forward force can be determined by clearing it in the expression described above:
According to Newton's Law of Gravitation, the Gravity Force is:
(1)
This expression can also be written as:
(2)
If we derive this force respect to the distance
between the two masses:
(3)
Taking into account are constants:
(4)
Or
(5)
In other words, this means how much does the Gravity Force changes with the distance between the two bodies.
More precisely this change is inversely proportional to the distance elevated to the cubic exponent.
As the distance increases, the Force decreases.
<h2>(c) The minus sign indicates that the bodies are being forced in the negative direction. </h2>This is because Gravity is an attractive force, as well as, a central conservative force.
This means it does not depend on time, and both bodies are mutually attracted to each other.
<h2>(d) </h2>In the first answer we already found the decrease rate of the Gravity force respect to the distance, being its unit :
(5)
We have a force that decreases with a rate 1 when
:
(6)
Isolating :
(7)
In addition, we have another force that decreases with a rate 2 when
:
(8)
Isolating :
(9)
Making (7)=(9):
(10)
Then isolating :
Solving and taking into account the units, we finally have:
>>>>This is how fast this force changes when
Answer:
A) vectors: veloicty, force
scalar: speed, work
B) t = 1.75 s, C) v = - 17 2 m / s
Explanation:
We answer each part separately
A) A vector magnitude has magnitude and direction instead a scalar magnitude has only magnitude
vector quantities: the speed of a car number is the magnitude and direction is where it goes
Force, the number is the magnitude and above that applies gives direction
Scalar magnitude: how quickly the number of the speedometer of the car
Temperature, work
B) I = 15 m height to the soil and get to calculate time = 0
y = y₀ + v₀ t - ½ g t²
as the ball is loose its initial velocity is zero
0 = 0 +0 - ½ g t²
t =
t =
t = 1.75 s
C) the velocity to the reach the floor
v = vo - g t
v = 0 - g t
v = - 9.8 1.74
v = - 17 2 m / s
The negative signt iindicates that the speed goes down