A 0.54 kg air hockey puck is initially at rest. What will it's kinetic energy energy be after a net force of 0.56 N acts on it f
1 answer:
Answer:
Kf = 470 mJ
Explanation:
- According the work-energy theorem, the change in the kinetic energy of one object, is equal to the net work done on it.
- Since the puck is initially at rest, the change is kinetic energy is just the final kinetic energy of the puck.
- Assuming that the net force is horizontal, and causes a horizontal displacement also, we can find the net work on the puck as follows:
- As we have already said, (1) is equal to the final kinetic energy of the puck:
- ⇒ Kf = 470 mJ (2)
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Answer:
6.05 cm
Explanation:
The given equation is
2 aₓ(x-x₀)=( Vₓ²-V₀ₓ²)
The initial head velocity V₀ₓ =11 m/s
The final head velocity Vₓ is 0
The accelerationis given by =1000 m/s²
the stopping distance = x-x₀=?
So we can wind the stopping distance by following formula
2 (-1000)(x-x₀)=[]
x-x₀=6.05* m
=6.05 cm
Answer:
0.1 m
Explanation:
F = Force exerted on spring = 3 N
k = Spring constant = 60 N/m
x = Displacement of the block
As the energy of the system is conserved we have
The position of the block is 0.1 from the initial position.