The law of conservation has been stated that the mass and energy has neither be created nor destroyed in a chemical reaction.
The law of conservation has been evident when there has been an equal number of atoms of each element in the chemical reaction.
<h3>Conservation law</h3><h3 />
The given equation has been assessed as follows:
The reactant has absence of hydrogen, while hydrogen has been present in the product. Thus, the reaction will not follow the law of conservation.
The number of atoms of each reactant has been different on the product and the reactant side. Thus, the reaction will not follow the law of conservation.
The reactant has the presence of carbon, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
The product has the presence of hydrogen, while it has been absent in the reactant. Thus, the reaction will not follow the law of conservation.
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Answer:
53.1 mL
Explanation:
Let's assume an ideal gas, and at the Standard Temperature and Pressure are equal to 273 K and 101.325 kPa.
For the ideal gas law:
P1*V1/T1 = P2*V2/T2
Where P is the pressure, V is the volume, T is temperature, 1 is the initial state and 2 the final state.
At the eudiometer, there is a mixture between the gas and the water vapor, thus, the total pressure is the sum of the partial pressure of the components. The pressure of the gas is:
P1 = 92.5 - 2.8 = 89.7 kPa
T1 = 23°C + 273 = 296 K
89.7*65/296 = 101.325*V2/273
101.325V2 = 5377.45
V2 = 53.1 mL
Magnesium dichloride or Magnesium chloride
For any spontaneous process, universe entropy intensifies is known as the second law of thermodynamics.
<h3>What is entropy?</h3>
Entropy is defined as the degree of randomness or disorderliness of a system.
The entropy of a system generally increases for any spontaneous process.
This is according to the second law of thermodynamics.
In conclusion, the entropy of a system is the a measure of randomness of the system.
Learn more about entropy at: brainly.com/question/21578229
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Answer:
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Explanation:
Water potential = Pressure potential + solute potential
We have :
C = 0.15 M, T = 273.15 K
i = 1
The water potential of a solution of 0.15 m sucrose= 
(At standard temperature)
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
