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3 years ago

D. Write the name of the branched alkane next to the drawing of the molecule. (2 points)

Chemistry

1 answer:

lbvjy [14]3 years ago

7 0

Answer: hello your question lacks some data attached below is the missing data

answer :

a) 3-methyl heptane

b) 2-methyl pentane

c) 2-methyl heptane

d) 2-methyl hexane

e) 3-methyl hexane

Explanation:

we will select the longest carbon chain as the branched alkane and name it

a) 3-methyl heptane ( first diagram )

b) 2-methyl pentane ( second diagram )

c) 2-methyl heptane ( third diagram )

d) 2-methyl hexane ( fourth diagram )

e) 3-methyl hexane ( fifth diagram )

Note : sixth diagram = first diagram 

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Give the major force between ethanol and rubbing alcohol.

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3 years ago

When 9.2 g of frozen N2O4 is added to a 0.50 L reaction vessel and the vessel is heated to 400 K and allowed to come to equilibr

Amanda [17]

Answer: The value of $K_c$ for the given reaction is 1.435

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of $N_2O_4$ = 9.2 g

Molar mass of $N_2O_4$ = 92 g/mol

Volume of solution = 0.50 L

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{9.2g}{92g/mol\times 0.50L}\\\\\text{Molarity of solution}=0.20M$

For the given chemical equation:

$N_2O_4(g)\rightleftharpoons 2NO_2(g)$

Initial: 0.20

At eqllm: 0.20-x 2x

We are given:

Equilibrium concentration of $N_2O_4$ = 0.057

Evaluating the value of 'x'

$\Rightarrow (0.20-x)=0.057\\\\\Rightarrow x=0.143$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NO_2]^2}{[N_2O_4]}$

$[NO_2]_{eq}=2x=(2\times 0.143)=0.286M$

$[N_2O_4]_{eq}=0.057M$

Putting values in above expression, we get:

$K_c=\frac{(0.286)^2}{0.143}\\\\K_c=1.435$

Hence, the value of $K_c$ for the given reaction is 1.435

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Answer:

1) volumetric

2) graduated

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Explanation:

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On the other hand, graduated glassware can measure a range of volumes of liquid. However, a volumetric glassware is still required where a high degree of accuracy is important.

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