<h3>
Answer:</h3>
D. CH₃O₆
<h3>
Explanation:</h3>
- We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84
We are supposed to determine the empirical formula of the compound;
- We need to know what is an empirical formula;
- An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.
In this case;
The ratio of C : H : O is 14 : 42 : 84
- Note, this is not the simplest ratio.
But we can simplify further to get the simplest whole number ratio;
- Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6
- Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6
- Therefore, the empirical formula of the compound is CH₃O₆
Answer:
Percent error = 3.7%
Explanation:
Given data:
Density of Al cylinder = ?
Weight of cylinder = 18 g
Diameter = 1.3 cm
Height = 5.2 cm
Actual density of Al = 2.7 g/cm³
Percent error = ?
Solution:
First of all we will calculate the volume of cylinder through given formula.
V = πr²h
r = diameter /2
V = 22/7 × (0.65 cm)²× 5.2 cm
V = 22/7 × 0.4225cm²× 5.2 cm
V = 6.89 cm³
Now we will calculate the density.
d = m/v
d = 18 g/ 6.89 cm³
d = 2.6 g/cm³
Percent error:
Percent error = measured value - actual value /actual value × 100
Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³ × 100
Percent error = 3.7%
Negative sign shows that measured or experimental value is less than actual value.
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