Assuming that the stone is thrown vertically... let's say it's a 1 kg stone.It doesn't matter if it's thrown upwards or downwards as (assuming no air friction) it will pass the original throwing point with the same downwards velocity as it had upwards, 3 seconds previously. So it starts with 1/2 m v^2 = 0.5 * 1 * 15^2 = 112.5 J of keThen k.e. gained = gpe lostk.e. gained = m g h = 1 * 10 * 50 = 500 J of Ke gainedso the final (total) ke is 612.5 J which = 1/2 m v^2 = 0.5 v^2 here
so 0.5 v^2 = 612.5so v^2 = 1225so v = 35 m/s
Answer:
15.68 m/s
Explanation:
Given that,
She catches the ball 3.2 s later at the same height from which it was thrown.
When it reaches the maximum height, its height is equal to 0.
It will move under the action of gravity.
![t=\dfrac{2u}{g}](https://tex.z-dn.net/?f=t%3D%5Cdfrac%7B2u%7D%7Bg%7D)
2 here comes for the time of ascent and descent.
So,
![u=\dfrac{tg}{2}\\\\u=\dfrac{3.2\times 9.8}{2}\\\\u=15.68\ m/s](https://tex.z-dn.net/?f=u%3D%5Cdfrac%7Btg%7D%7B2%7D%5C%5C%5C%5Cu%3D%5Cdfrac%7B3.2%5Ctimes%209.8%7D%7B2%7D%5C%5C%5C%5Cu%3D15.68%5C%20m%2Fs)
So, the initial upward speed of the ball is 15.68 m/s.
Answer: A man known as H.M suffered from <u>epileptic seizures </u>after an operation removed portions of his <u>memory</u>.
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Explanation:
Just took that test the answer is perpendicular to the wave motion