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xxTIMURxx [149]
2 years ago
9

I NEED HELP ON THIS WORTH 20 POINTS :)

Chemistry
2 answers:
Kamila [148]2 years ago
6 0

Answer:

option c is correct

Explanation:

please mark me as brainlist

Arturiano [62]2 years ago
4 0

Answer: C. mollusca and arthropoda

                                                                           

Explanation:

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To produce large tomatoes that are resistant to cracking and splitting some seeds companies use the pollen from one variety of t
rodikova [14]

Answer:

cross pollination

Explanation:

is when two types of plants are mixed to create a better or hardier plant

4 0
3 years ago
Observation and assessment are most effective when
Artist 52 [7]
I think the answer is A. Hope that helped :)
6 0
3 years ago
Is water an element compound or mixture
timama [110]
It is a Compound.

Water can't be a mixture because it is chemically bonded and cannot be separated into H2 and O by physical means.

And water cannot be an element, because it is made of atoms of different types [H and Oxygen]
4 0
3 years ago
In a chemical equation what name does the left side have
Pachacha [2.7K]
A chemical equation is a short hand expression of a chemical reaction. There aretwo<span> parts to a chemical equation. The reactants are the elements or compounds on the left side of the arrow (-->). The elements and compounds to the right of the arrow are the products.</span>
4 0
3 years ago
Suppose Gabor, a scuba diver, is at a depth of 15m15m. Assume that: The air pressure in his air tract is the same as the net wat
alexandr1967 [171]

Answer:

The ration of molar concentration is "2.5".

Explanation:

The given values are:

Average density of salt water,

= 1.03 \ g/cm^3

Net pressure,

= 2.00 \ atm

Increase in pressure,

= 1.00 \ atm

Now,

The under water pressure will be:

=  \frac{15 \ m}{10}\times 1 \ atm +1 \ atm

=  1.5\times 1+1

=  1.5+1

=  2.5 \ atm

hence,

The ratio will be:

=  \frac{(\frac{n}{V})_{15m} }{(\frac{n}{V})_{surface} }

or,

=  \frac{P}{P_s}

=  \frac{2.5}{1}

=  2.5

7 0
3 years ago
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