The bar graph below shows the number of tickets sold for each of the seating sections in a baseball stadium.

Physics

2 answers:

Juliette [100K]3 years ago

6 0

A. 800 bleacher seats were sold

frosja888 [35]3 years ago

4 0

800 bleachers was sold

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Time taken by the rubber-soled shoes to reduce a person's potential from 3.00×10³ V to 100V is 3.91s

The initial potential difference $\Delta V_o$ is related to the final potential difference $\Delta V$ by

$\Delta V=\Delta V_{o} e^{-t / \tau}$

Our target is to find t, so we rearrange equation (1) for t to be

$\Delta V=\Delta V_{o} e^{-t / RC}\\ \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) = \frac{-t}{RC}\\ t= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \tag{2}$

The body has a capacitance 150 pF while the foot has a capacitance 80 pF and both are in parallel connection. So, the equivalent capacitance is

$C= 150 \mathrm{~pF} + 80 \mathrm{~pF} = 230 \mathrm{~pF}$

The shoes of the rubber-soled has resistance $R=5000 \mathrm{~M\Omega}$ . Plug the values for $\Delta V, \Delta V_o$ and C into equation (2) to get the time t.

$t&= -RC \ln \left ( \frac{\Delta V}{\Delta V_{o}} \right ) \\ &= -( 5000 \times 10^{6} \mathrm{~\Omega})(230 \times 10^{-12} \mathrm{~F}) \ln \left ( \frac{100\mathrm{~V}}{3000 \mathrm{~V}} \right ) \\ &= {3.91 \mathrm{~s}}$