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QveST [7]
3 years ago
14

1. How much heat is required to raise the temperature of 57.8kg of silver from 17.0°C to

Physics
1 answer:
Y_Kistochka [10]3 years ago
7 0
Answer: unknown so the second one
I hope this helps you with your stuff
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A car slows down at -5.00 m/s^s until it comes to a stop after traveling 15.0 m.
mylen [45]

Answer:

2.45

Explanation:

5 0
3 years ago
A car with a mass of 1.1 × 103 kilograms hits a stationary truck with a mass of 2.3 × 103 kilograms from the rear end. The initi
snow_lady [41]

Answer:

The velocity of the truck after this elastic collision is 15.7 m/s            

Explanation:

It is given that,

Mass of the car, m_1=1.1\times 10^3\ kg

Mass of the truck, m_2=2.3\times 10^3\ kg

Initial velocity of the car, u_1=22\ m/s

Initial velocity of the truck, u₂ = 0

After the collision the velocity of the car is, v₁ = -11 m/s

Let v₂ is the velocity of the truck after this elastic collision. Using the conservation of momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

1.1\times 10^3\times 22+0=1.1\times 10^3\times (11)+2.3\times 10^3\times v_2    

v_2=15.7\ m/s

So, the velocity of the truck after this elastic collision is 15.7 m/s. Hence, the correct option is (c).

4 0
3 years ago
Two foam peanuts become equally charged as they fall out of a cardboard box. Each foam peanut carries a charge of 8 x 10^-4 C. I
jok3333 [9.3K]

Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

F_e=9\,\,10^9\,  \,  \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\,  \,  \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N

which agrees with answer B provided.

7 0
3 years ago
Arsenic diffusion in Si: Arsenic is diffused into a thick slice of silicon with no previous arsenic in it at 1100ºC. If the surf
Rainbow [258]

Answer:

Diffusion time is 7.42 h

Solution:

As per the question:

Temperature, T = 1100^{\circ}C

Surface concentration of arsenic, C_{S} = 5.0\times 10^{18}\ atoms/cm^{3}

Surface concentration below Silicon surface, C_{x} = 1.5\times 10^{16}\ atoms/cm^{3}

D = 3.0\times 10^{- 14}\ cm^{2}/s

x = 1.2\mu m = 1.2\times 10^{- 4}\ cm

Initial concentration at t = 0, C_{o} = 0

Now, by using Flick's second eqn:

\frac{C_{S} - C_{x}}{C_{x} - C_{o}} = erf(\frac{x}{\sqrt{Dt}})

Thus by putting appropriate values:

\frac{5.0\times 10^{18} - 1.5\times 10^{16}}{5.0\times 10^{18}} = erf(\frac{1.2\times 10^{- 4}}{2\sqrt{3.0\times 10^{- 14}t}})

0.997 = erf(\frac{364.4}{\sqrt{t}})              (1)

Now,

erf(z) = 0.997

Now, from error function values tabulation:

For z = 2.0, erf(z) = 0.998

For z = 2.2, erf(z) = 0.995

Now,

With the help of linear interpolation method:

\frac{z - 2}{2.2 - 2.0} = \frac{0.997 - 0.995}{0.998 - 0.995}

z = 2.12

Now, using eqn (1) and above value:

\frac{364.4}{\sqrt{t}} = 2.12

t = (\frac{364.4}{2.12})^{2} = 26700 s

t = \frac{26700}{3600} = 7.42\ h

7 0
3 years ago
The table represents the speed of a car in a northern
Sidana [21]

Answer:

O Column 1 should be titled "Time," and Column 2 shouldbe titled "Velocity,"

O Column 1 should be titled "Velocity," and Column 2 should be titled "Time."

O Column 1 should be titled "Time," and Column 2 should be titled "Acceleration."

O Column 1 should be titled "Acceleration," and Column 2 should be titled "Time."

4 0
3 years ago
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