1. How much heat is required to raise the temperature of 57.8kg of silver from 17.0°C to
1 answer:
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Answer:
total work is 99.138 kJ
Explanation:
given data
diameter = 5 cm
depth = 75 m
density = 1830 kg/m³
to find out
the total work
solution
we know mass of volume is
volume =
volume =
so
work required to rise the mass to the height of x m
dw = gx dx
so total work is integrate it with 0 to 75
w =
w = × 0.05² × 1830× 9.81×
w = 99138.53 J
so total work is 99.138 kJ