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3 years ago

What are some ways to deal with stress? HELP

Physics

2 answers:

stira [4]3 years ago

6 0

Answer:

dear the other side is the hardich the value that indicates that the other hand if one of triangle ABC news and information or have any further information on the value of x the ki friend my dear the ki aadami you are girl or by phone

Vinvika [58]3 years ago

4 0

Answer:

play games

do meditation

take a long breath

be calm and relax

share your stress

get help from elders

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A 15.0-mW laser puts out a narrow beam 2.00 mm indiameter.

UkoKoshka [18]

Explanation:

It is known that formula for energy per unit area per unit time is as follows.

S = $\frac{P}{A}$

= $\frac{P}{\pi \times r^{2}} = \frac{4P}{\pi d^{2}}$

$c \epsilon_{o} E^{2} = \frac{4P}{\pi d^{2}}$

E = $\sqrt{\frac{4P}{\pi d^{2} c \epsilon_{o}}}$

Now, putting the values we will calculate the electric field as follows.

E = $\sqrt{\frac{4P}{\pi d^{2} c \epsilon_{o}}}$

= $\sqrt{\frac{4 \times 15 \times 10^{-3} W}{3.14 \times (2mm \times \frac{1m}{1000 mm})^{2} \times 3 \times 10^{8} \times 8.85 \times 10^{-12}}}$

= 1341.03 V/m

Now, we will calculate the average magnetic field as follows.

B = $\frac{E}{c}$

= $\frac{1341.03 V/m}{3 \times 10^{8} m/s}$

= $4.47 \times 10^{-6}$ T

= $4.47 \mu T$

Thus, we can conclude that the average (rms) value of the magnetic field is $4.47 \mu T$ .

3 0

3 years ago

⦁ What is the mass of air in a room that has dimensions of 10m x 20m x 4 m? Use values from the book to show your work.

agasfer [191]

The mass of an air can be derived from the equation from density, where D=m/v. Multiply each sides by v making the equation m= Dv. Substituting the values for density and volume. m = (1.225 kg/m3)(10x20x4)m3 gives a result of 980 kg.

8 0

4 years ago

Which statement below is false? A) Weight depends on the force of gravity. B) Mass is the amount of matter in an object. C) Mass

grin007 [14]

D because weight is not a constant, however; Matyer is a constant

8 0

3 years ago

Read 2 more answers

A sled and its rider are moving at a speed of 4.0 m/s along a horizontal stretch of snow. The snow exerts a kinetic frictional f

ehidna [41]

Answer:

The acceleration of the sled is "0.49 m/s²". A further explanation is given below.