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lianna [129]
3 years ago
15

The spectrophotometer measures what property of a solution? Group of answer choices

Physics
1 answer:
Yanka [14]3 years ago
5 0

Answer:

B. The ability of the solute molecules only to absorb the energy of light (photons) at a specific wavelength.

Explanation:

Spectrophotometry is the quantitative measurement of the reflection or transmission properties of a material as a function of wavelength. In case of a solution, both, solute and solvent would absorb the energy on an specific lenghtwave of light if they have a absortion coefficient diffrent of 0. The solvent could absorb energy of light, but it´s not typical, for example water does not absorb light in any lenghtwave. Therefore, for practical uses, we consider that only the solute absorbes, and it case the solvent does, that should be taken into account for the solute concentration calculation.

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Which statement best describes the law of conservation of energy?
Phantasy [73]
<span>The correct option is C. Energy cannot be created or destroyed. This statement is known as law of conservation of energy, and it implies that whenever a certain form of energy does change, the loss of this form of energy must have converted into an another type of energy. A typical example is an object falling to the ground: initially, the object has gravitational potential energy. As the object falls down, it loses potential energy (since its altitude from the grounf decreases), but it acquires kinetic energy (because its velocity increases). In this example, potential energy has converted into kinetic energy, but the total energy of the object has remained constant.</span>
8 0
3 years ago
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A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
Density of water 1000kgper m^3 What will be the volume of 3500<br>kg water​
skad [1K]

Answer:

<em>The volume of water is 3.5 cubic meter</em>

Explanation:

<u>Density </u>

The density of a substance or material is the mass per unit volume. The density varies with temperature and pressure.

The formula to calculate the density of a substance of mass (m) and volume (V) is:

\displaystyle \rho=\frac{m}{V}

We are given the density of water as \rho=1,000\ kg/m^3.It's required to find the volume of m=3,500 kg of water. Solving for V:

\displaystyle V=\frac{m}{\rho}

\displaystyle V=\frac{3,500}{1,000}

V=3.5\ m^3

The volume of water is 3.5 cubic meter

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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
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In the diagrams, the solid green line represents Earth's rotational axis and the dashed red line represents the magnetic field a
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Answer:

b

Explanation:

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