Answer:
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Explanation:
Total force required = Mass x Acceleration,
F = ma
Here we need to consider the system as combine, total mass need to be considered.
Total mass, a = m₁+m₂+m₃ = 584 + 838 + 322 = 1744 kg
We need to accelerate the group of rocks from the road at 0.250 m/s²
That is acceleration, a = 0.250 m/s²
Force required, F = ma = 1744 x 0.25 = 436 N
Force must be applied to m₁ to move the group of rocks from the road at 0.250 m/s² = 436 N
Answer:
Explanation:
For a wave, the speed is the distance traveled by a given point on the wave (such as a crest) in a given period of time. So while wave frequency refers to the number of cycles occurring per second, wave speed refers to the meters traveled per second
Answer:
A
Explanation:
![work = force \times distance](https://tex.z-dn.net/?f=work%20%3D%20force%20%5Ctimes%20distance)
![work = 1100 \times 0.5](https://tex.z-dn.net/?f=work%20%3D%201100%20%5Ctimes%200.5)
![= 550 \: j](https://tex.z-dn.net/?f=%20%3D%20550%20%5C%3A%20j)
hope it helped a lot
pls mark brainliest with due respect .
Answer:
Decreases by
times
Explanation:
The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.
The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.
In other words, the sound intensity decreases as inversely proportional to the squared of the distance. i.e. ![$\frac{1}{r^2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7Br%5E2%7D%24)
In the context when the distance was 3 m, the intensity of the sound was = ![$\frac{1}{9}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B9%7D%24)
But when the distance became 6 cm or 0.06 m, the sound intensity decreases by = ![$\frac{1}{0.06^2}$](https://tex.z-dn.net/?f=%24%5Cfrac%7B1%7D%7B0.06%5E2%7D%24)
=
times
The weights in newtowns for the given masses are
<span> masses 22.1, 33.5, 41.3, 59.2, 78
weights 216.58N 328.3N 404.74N 580.16N 764.4N
e.g, for m=22.1kg, W=22.1kgx9.8N/kg =216.58N</span>