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wel
3 years ago
6

What is the PEN number for Oxygen?

Chemistry
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

8

Explanation:

g o o g l e d it

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maw [93]

Answer:then he has a lot of gas

Explanation

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3 years ago
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The rate of weathering depends on?
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Amount of water in air

Temperature of the area
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Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble
Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

           AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq) ............. (1)

     K_{sp} = [Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}

Reaction for the complex formation is as follows.

          Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq) ........... (2)

          K_{f} = \frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}

When we add both equations (1) and (2) then the resultant equation is as follows.

             AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq) ............. (3)

Therefore, equilibrium constant will be as follows.

                       K = K_{f} \times K_{sp}

                          = 1.0 \times 10^{8} \times 1.8 \times 10^{-10}

                          = 1.8 \times 10^{-2}

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of NH_{3} for complexation. This means we have to set

               [Ag^{+}] = [Cl^{-}]

                          = \frac{0.010 mol}{1 L}

                          = 0.010 M

For the net reaction, AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)

Initial :                             0.010         x                     0                           0

Change :                    -0.010         -0.020             +0.010                +0.010

Equilibrium :                   0            x - 0.020           0.010                 0.010

Hence, the equilibrium constant expression for this is as follows.

              K = \frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}

     1.8 \times 10^{-2} = \frac{0.010 \times 0.010}{(x - 0.020)^{2}}

             x = 0.0945 mol      

or,          x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of NH_{3} needed to be added is 0.095 mol.

3 0
4 years ago
Calculate the formula/molecular mass of following
ddd [48]

Answer:

Refer to the period table. Use the atomic mass for calculation. Multiply the atomic mass with the number of atoms. For example, Al2(SO4)3. (27 × 2) + (32 x 3) + (16 x 12) = molecular mass

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How much salt is required to make 250g of a 5.0% saline solution?
Harlamova29_29 [7]

Answer:

do you have notes for this if I saw an example I might know the answer

3 0
4 years ago
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