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wel
3 years ago
6

What is the PEN number for Oxygen?

Chemistry
1 answer:
nataly862011 [7]3 years ago
7 0

Answer:

8

Explanation:

g o o g l e d it

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How much heat will be absorbed by 395g of water when it's temperature is raised by 55°C​
Firdavs [7]

Answer:

\boxed{\text{91 kJ}}

Explanation:

The formula for the heat released is

q = mCΔT

Data:

 m = 395 g

 C = 4.184 J·°C⁻¹g⁻¹

ΔT = 55 °C

Calculations:

q = 395 × 4.184 × 55 = 91 000 J = 91 kJ

The water will absorb \boxed{\textbf{91 kJ}} of energy.

3 0
3 years ago
So anyone wanna be a Good Samaritan and help ya girl out
goldenfox [79]

The answer is JESUS BECAUSE HE IS ALWAYS THE ANSWER

8 0
3 years ago
What is the number of moles of ammonia gas formed when 0.5 mole of nitrogen gas is reacted with excess of hydrogen gas?​
Troyanec [42]

Answer: 1.5mol NH3

Explanation: 1N2+3H2= NH3

                      0.5 mol N2x 3NH3/1molN2= 0.5x3= 1.5mol NH3

7 0
2 years ago
Convert 4.500000000 to scientific notation
aniked [119]
I think it’s 4.5 x 10^9
7 0
3 years ago
Calculate the moles of calcium chloride (CaCl2) needed to react in order to produce 85.00 grams of calcium carbonate (CaCO3). us
BartSMP [9]

Answer:

0.85 mole

Explanation:

Step 1:

The balanced equation for the reaction of CaCl2 to produce CaCO3. This is illustrated below:

When CaCl2 react with Na2CO3, CaCO3 is produced according to the balanced equation:

CaCl2 + Na2CO3 -> CaCO3 + 2NaCl

Step 2:

Conversion of 85g of CaCO3 to mole. This is illustrated below:

Molar Mass of CaCO3 = 40 + 12 + (16x3) = 40 + 12 + 48 = 100g/mol

Mass of CaCO3 = 85g

Moles of CaCO3 =?

Number of mole = Mass /Molar Mass

Mole of CaCO3 = 85/100

Mole of caco= 0.85 mole

Step 3:

Determination of the number of mole of CaCl2 needed to produce 85g (i.e 0. 85 mole) of CaCO3.

This is illustrated below :

From the balanced equation above,

1 mole of CaCl2 reacted to produced 1 mole of CaCO3.

Therefore, 0.85 mole of CaCl2 will also react to produce 0.85 mole of CaCO3.

From the calculations made above, 0.85 mole of CaCl2 is needed to produce 85g of CaCO3

5 0
3 years ago
Read 2 more answers
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