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pishuonlain [190]
3 years ago
6

Iron is denser than helium. True or false

Chemistry
1 answer:
Delicious77 [7]3 years ago
4 0

Explanation:

Elements heavier than Helium are synthesized in a number of environments. For elements that are lighter than Iron, those elements are synthesized during various phases in the evolution of massive stars. For elements heavier than Iron, one needs quite a bit of energy input to form these heavy elements.

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Read: https://kids.britannica.com/kids/article/DNA/390730 (Links to an external site.)
kompoz [17]

Answer:

im not doing your whole homework. but ill give you  one cent ;>, whats ur paypal

Explanation:

4 0
3 years ago
1. Which is a chemical property of wood?<br> conductivity<br> flammability<br> malleability
Allisa [31]

Answer:

Wood consists mainly of organic substances (99% of the total mass). Elemental chemical composition of wood of different breeds is practically the same. Absolutely dry wood on average contains 49% of carbon, 44% of oxygen, 6% of hydrogen, 0.1-0.3% of nitrogen. When burning wood remains its inorganic part - ash.

So the answer is flammability because wood is flammable.

3 0
3 years ago
How many atoms of lead are contained in 0.532mol?​
Colt1911 [192]

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

6 0
3 years ago
Calculate the energy required to heat 566.0mg of graphite from 5.2°C to 23.2°C. Assume the specific heat capacity of graphite un
maw [93]

Answer:

7.23 J

Explanation:

Step 1: Given data

  • Mass of graphite (m): 566.0 mg
  • Initial temperature: 5.2 °C
  • Final temperature: 23.2 °C
  • Specific heat capacity of graphite (c): 0.710J·g⁻¹K⁻¹

Step 2: Calculate the energy required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.710J·g⁻¹K⁻¹ × 0.5660 g × (23.2°C-5.2°C)

Q = 7.23 J

6 0
3 years ago
How does the lens of a light microscope work?
ohaa [14]
D. the reflection of each concave lens makes the object appear larger
8 0
3 years ago
Read 2 more answers
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