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ArbitrLikvidat [17]
3 years ago
13

Please help me

Mathematics
1 answer:
natka813 [3]3 years ago
6 0

Answer:

The answer is Y=3x

when x is 0, y is 0

y=3x

Y= 3 X 0 = 0 (correct)

when x is 1, y is 3

y=3x

y=3 X 1= 3 (correct)

when x is 2 , y is 6

y=3x

y= 3 X 2= 6 (correct)

when x is 3, y is 9

y=3x

y= 3 X 3= 9 (correct)

when x is 4, y is 12

y=3x

y= 3 X 4= 12 ( Correct)

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Step-by-step explanation

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There is 45.9 inches for the whole year so
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Can I get some help..please?​
krek1111 [17]

Answer:

-2 and 21/50

Step-by-step explanation:

PEMDAS says that paranthases go first, so we solve 2 and 1/5 minus 33/12. 2 and 1/5 simplifies to the improper fraction, 11/5. Then we find a common denominater between 11/5 and 33/12 to get 60. 11/5=132/60, and 33/12=165/60. (132/60)-(165/60)=-33/60. Then we multipl that by 4 and 2/5, which can simplify to the improper fraction, 22/5. (22/5)*(-33/60) is -726/300, and simplifies to -2 and 21/50. Hope this helps!

7 0
3 years ago
Write 90,523 in Word form
azamat
Ninety thousand five hundred twenty three
3 0
3 years ago
Read 2 more answers
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
3 years ago
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