If the half-life of niobium-91 is 680 years, how long will it take for the decay described in the previous question?
2 answers:
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The magnitude of the adhesive force allows the top block to remain
attached to the bottom when the blocks and the wire are balanced.
The option that must be true is;
Reason:
The tension exerted by the wire attached to the top block = T
Magnitude of the adhesive =
Weight of the top block =
Weight of the bottom block =
Given that with the exertion of the tension, the two blocks remain at rest, we have;
- T =
+
The adhesive causes the bottom block to remain attached to the top block, we have;
Therefore, the magnitude of the adhesive force adds the bottom weight, to the top, weight, which gives;
The magnitude of the adhesive force = The weight of the bottom block
Therefore;
=
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Answer:
The answer to the question is;
The total potential energy of the mass on the spring when the mass is at either endpoint of its motion is 5.0255 Joules.
Explanation:
To answer the question, we note that the maximum speed is 2.30 m/s and the mass is 1.90 kg
Therefore the maximum kinetic energy of motion is given by
Kinetic Energy, KE =
Where,
m = Attached vibrating mass = 1.90 kg
v = velocity of the string = 2.3 m/s
Therefore Kinetic Energy, KE = ×1.9×2.3² = 5.0255 J
From the law of conservation of energy, we have the kinetic energy, during the cause of the vibration is converted to potential energy when the mass is at either endpoint of its motion
Therefore Potential Energy PE at end point = Kinetic Energy, KE at the middle of the motion
That is the total potential energy of the mass on the spring when the mass is at either endpoint of its motion is equal to the maximum kinetic energy.
Total PE = Maximum KE = 5.0255 J.