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Agata [3.3K]
3 years ago
14

Quadrilateral ABCD will be dilated about the origin by a scale factor of 1/3 and then reflected across the y-axis.

Mathematics
1 answer:
Luda [366]3 years ago
4 0

Answer:

See explanation

Step-by-step explanation:

The coordinate of ABCD is not given; So, I will solve using general coordinates (x,y).

First, ABCD is dilated by 1/3.

The rule is:

(x,y) \to \frac{1}{3}(x,y)

This gives

(x,y) \to (\frac{x}{3},\frac{y}{3})

Next, it is reflected across y-axis.

The rule is:

(x,y) \to (-x,y)

So, we have:

(\frac{x}{3},\frac{y}{3}) \to (-\frac{x}{3},\frac{y}{3})

So, the complete transformation is:

(x,y) \to (\frac{x}{3},\frac{y}{3}) \to (-\frac{x}{3},\frac{y}{3})

Assume that:

A = (1,3)

The transformation will be:

A' = (-\frac{1}{3},\frac{3}{3})

A' = (-\frac{1}{3},1)

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