Question

Quadrilateral ABCD will be dilated about the origin by a scale factor of 1/3 and then reflected across the y-axis.

Answer 1

Answer:

See explanation

Step-by-step explanation:

The coordinate of ABCD is not given; So, I will solve using general coordinates (x,y).

First, ABCD is dilated by 1/3.

The rule is:

$(x,y) \to \frac{1}{3}(x,y)$

This gives

$(x,y) \to (\frac{x}{3},\frac{y}{3})$

Next, it is reflected across y-axis.

The rule is:

$(x,y) \to (-x,y)$

So, we have:

$(\frac{x}{3},\frac{y}{3}) \to (-\frac{x}{3},\frac{y}{3})$

So, the complete transformation is:

$(x,y) \to (\frac{x}{3},\frac{y}{3}) \to (-\frac{x}{3},\frac{y}{3})$

Assume that:

$A = (1,3)$

The transformation will be:

$A' = (-\frac{1}{3},\frac{3}{3})$

$A' = (-\frac{1}{3},1)$