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Bezzdna [24]
3 years ago
15

I need help on working this out. Can anyone help me out?

Mathematics
1 answer:
Tasya [4]3 years ago
8 0
Gosh that looks hard. but i wish you the best of luck on it
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Solve x-3/6 divided by 3-x/2 Please show work HEELLLLP PLEEASE I need help ASAP
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When dividing fractions remember to: keep/change/change.
keep the first fraction, change the division sign to multiplication, and lastly change your second fraction to its reciprocal. 

x-3/6 * 2/3-x
simplify and cancel (x-3) and (3-x) to -1
final answer: -1/3
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3 years ago
True or False. Explain your answer. csc^-1[csc(-pi/4)]=-pi/4 sec[sec^-1(sqrt3)]=sqrt3
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7 0
3 years ago
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A university law school accepts 6 out of every 11 applicants. If the school accepted 564 students, find how many applications th
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5 0
3 years ago
Please help fast!!!! Find the seventh term of the geometric sequence if a1=7 and r=3
statuscvo [17]

Answer:

15309 Im pretty sure

Step-by-step explanation:

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=7(3^7)

7 x 2187=15309

6 0
2 years ago
<img src="https://tex.z-dn.net/?f=15%20x%5E%7B2%7D%20%2B14x-49%3D0" id="TexFormula1" title="15 x^{2} +14x-49=0" alt="15 x^{2} +1
Alex777 [14]
15x^2+14x-49=0\\\\&#10;Terms:\\&#10;a=15\ \ \ \ b=14\ \ \ \ c=-49\\&#10;Quadratic\ Formula:\\\\&#10;x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\&#10;x=\dfrac{-14\pm\sqrt{196+2,940}}{30}\\\\&#10;x=\dfrac{-14\pm\sqrt{3,136}}{30}\\\\&#10;x=\dfrac{-14\pm56}{30}

Roots:\\\\&#10;x'=\dfrac{-14+56}{30}\\\\&#10;x'=\dfrac{42}{30}\\\\&#10;x'=\dfrac{21}{15}\\\\&#10;\boxed{x'=\dfrac{7}{5}}\\\\\\\\&#10;x''=\dfrac{-14-56}{30}\\\\&#10;x''=\dfrac{-70}{30}\\\\&#10;\boxed{x''=\dfrac{-7}{3}}
8 0
3 years ago
Read 2 more answers
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