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Bezzdna [24]
3 years ago
15

I need help on working this out. Can anyone help me out?

Mathematics
1 answer:
Tasya [4]3 years ago
8 0
Gosh that looks hard. but i wish you the best of luck on it
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The identity property of multiplication is also known as
Aleks04 [339]

Answer:

Identity Property of Multiplication Definition. This property is also known as the multiplication property of 1. It states that the result of multiplying any real number by 1 is the number itself.

Step-by-step explanation:


8 0
4 years ago
Read 2 more answers
Solve for x. X+ 2 1/5=5 3/5
Alexxandr [17]

Answer:

x=17/5

Step-by-step explanation:

2 1/5=11/5

5 3/5=28/5

------------------

x+11/5=28/5

x=28/5-11/5

x=17/5

3 0
3 years ago
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What type of answer will 2.25 + .75 have? Explain.
julia-pushkina [17]

Answer:

the answer will have a decimal but there is no such thing as type of answer.

there are many ways to answer this

5 0
3 years ago
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From a list of 100 grade 12 students numbered 00 to 99, a sample of ten is taken. For each example below, identify what sampling
Natali [406]

Answer:

Following are the solution to this question:

Step-by-step explanation:

We used sampling technique to collect samples throughout the instance of Options a and b because here each successive sample frame has the same gap of 10 (in the example) and in 'b' is 1, but we use a simple random sampling in 'b' and 'c' to collect the test because they can't follow any specific pattern from of the collecting systems here.

4 0
3 years ago
Please helpppppp meeee
yKpoI14uk [10]

Answer:

0.25     Converges

Step-by-step explanation:

First, we need to expand our series so that we get the following:

\sum _{n=1}^{\infty \:}\frac{n}{4^n}+\frac{1}{4^{n+1}}

We can then use the series ratio test on each term. (L < 1 = absolutely convergent)

\sum _{n=1}^{\infty \:}\frac{n}{4^n}

\lim_{n \to \infty} \frac{n}{4^{n}\\} =

⇒  converges

\sum _{n=1}^{\infty \:}\frac{1}{4^n^+1}

\lim_{n \to \infty} \frac{n}{4^{n}^+1\\}

⇒  converges

converges + converges

= converges

~Hope this helps! Once again, sorry if my explanation is a bit confusing~

8 0
3 years ago
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