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ipn [44]
2 years ago
11

PLEASE HELP ONLY NINE DAYS LEFT I WILL GIVE BRANLIEST

Physics
1 answer:
Snowcat [4.5K]2 years ago
6 0

Answer:

A A A

Explanation:

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Two cars cover the same distance in a straight line. Car A covers the distance at a constant velocity. Car B starts from rest an
Morgarella [4.7K]

Answer:

2.218 m/s; 4.4375 m/s; 0.01981 m/s²

Explanation:

for more details see the attached picture.

4 0
3 years ago
Determine the moment of inertia Ixx of the mallet about the x-axis. The density of the wooden handle is 860 kg/m3 and that of th
Yuki888 [10]

Complete Question

Diagram for this  shown on the first uploaded image

Answer:

The moment of inertia Ixx of the mallet about the x-axis is I{xx}= 0.119 kg \cdot m^2

Explanation:

From the question we are told that

        The density `of wooden handle is  \rho_w = 860 kg/m^3

        The density `of soft-metal head  is \rho_s =8000kg/m^3

Generally the mass of the wooden can be mathematically obtained with this formula

          m_w = \rho_w A_w l_w

Where A_w is mass of wooden handle which is  mathematically obtain with the formula

             A_w = \frac{\pi}{4} d^2_w

Where d_w is the diameter  of the wooden handle which from the diagram is

       27mm = \frac{27}{1000} = 0.027m

So  A_w = \frac{\pi}{4} * 0.027^2

      l_w is the length of the the wooden handle which is given in the diagram as   l_w = 315mm = \frac{315}{1000} = 0.315m

Substituting these value into the formula for mass

      m_w = 860 * (\frac{\pi}{4} * 0.027^2 ) *0.315

            = 0.155kg

Generally the mass of the soft-metal head can be mathematically obtained with this formula

           m_s = \rho_s A_s l_s

Where A_s is mass of soft-metal head which is  mathematically obtain with the formula

            A_s = \frac{\pi}{4} d^2_s

Where d_s is the diameter  of the soft-metal head which from the diagram is            

       36mm = \frac{36}{1000} = 0.036m

So  A_s = \frac{\pi}{4} * 0.036^2

 l_s is the length of the the soft-metal head which is given in the diagram

     as   l_s = 90mm = \frac{90}{1000} = 0.090m

Substituting these value into the formula for mass  

                  m_s = 8000 * (\frac{\pi}{4} * 0.036^2 ) *0.090

                       =0.733kg

Generally the mass moment of inertia about x-axis for the wooden handle is

                  (I_{xx})_w  =    [\frac{1}{3}m_w + l_w^2 ]  

Substituting values

                   (I_{xx})_w  =    [\frac{1}{3}*0.155 + 0.315^2 ]

                              =5.12*10^{-3}kg \cdot m^2  

Generally the mass moment of inertia about x-axis for the soft-metal head is

    (I_{xx})_s = [\frac{1}{12}m_s l_s ^2 + b^2]

Where b is the distance from the centroid to the axis of the head which is mathematically given as

                   b=l_w +\frac{d_s}{2}

Substituting values

                 b = 0.315 + \frac{0.036}{2}

                    = 0.336m

Now substituting values into the formula for mass moment of inertia about x-axis for soft-metal head

                            (I_{xx})_s = [\frac{1}{12} *0.733*  0.090^2 + 0.336^2]

                                      =0.113 kg \cdot m^2

Generally the mass moment of inertia about x-axis is mathematically represented as

         I_{xx} = (I_{xx})_w + (I_{xx})_s

                = [\frac{1}{3}m_w + l_w^2 ] + [\frac{1}{12}m_s l_s ^2 + b^2]

Substituting values

        I_{xx} = 5.12*10^{-3} +0.113

               I{xx}= 0.119 kg \cdot m^2

             

             

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