1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
snow_lady [41]
3 years ago
10

Determine the mass of 6.33 mol of iron(II) nitrate.

Chemistry
1 answer:
uysha [10]3 years ago
8 0

Answer:

1822.72 g

Explanation:

Applying,

n = R.M/M.M.................. Equation 1

Where n = number of moles of iron(II) nitrate, R.M = Reacting mass of iron(II) nitrate, M.M = molar mass of Iron(II) nitrate.

Make R.M the subject of the equation

R.M = n×M.M............. Equation 2

From the question,

Given: n = 6.33 mol

Constant: M.M of iron(II) nitrate = 287.95 g/mol

Substitute these values into equation 2

R.M = 6.33(287.95)

R.M = 1822.72 g

Hence the mass of iron(II) nitrate is 1822.72 g

You might be interested in
15. Within a voltaic cell,___
kobusy [5.1K]

Answer:

B. oxidation; reduction

Explanation:

A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.

1. This cell utilizes chemical reaction to generate electric.\

2. there two electrode anode and cathode

3. At Anode oxidation occurs

4. At cathode reduction occurs

5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.

  • oxidation is the process in which there is loss of electrons
  • Reduction is the process in which there is gain of electrons

___________________________________________________

Based on above discussion

At anode oxidation takes place

At cathode reduction takes place.

Hence, correct option is B. oxidation; reduction

7 0
3 years ago
Suppose you have a solution that is either an acid or a base. It doesn’t react with any metals. Is the pH of the solution more l
OverLord2011 [107]
Its more likely to be a four
4 0
3 years ago
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
Min : sec helium and nickel are classified as _____, which are pure substances that make up all kinds of matter
Sidana [21]

Helium which has a chemical formula of He is considered as a noble gas while Nickel which has a chemical formula of Ni is considered as metallic. Although both have different phases but they are both classified under the general category of “Elements”.

 

answer:

<span>elements</span>

4 0
3 years ago
How many grams of mercury would be contained in 15 compact fluorescent light bulbs?
zhenek [66]

Answer:

Grams of mercury= 0.06 g of Hg

Note: The question is incomplete. The complete question is as follows:

A compact fluorescent light bulb contains 4 mg of mercury. How many grams of mercury would be contained in 15 compact fluorescent light bulbs?

Explanation:

Since one fluorescent light bulb contains 4 mg of mercury,

15 such bulbs will contain 15 * 4 mg of mercury = 60 mg

1 mg = 0.001 g

Therefore, 60 mg = 0.001 g * 60 = 0.06 g of mercury.

Compact fluorescent lightbulbs (CFLs) are tubes containing mercury and noble gases. When electricity is passed through the bulb, electron-streams flow from a tungsten-coated coil. They collide with mercury atoms, exciting their electrons and creating flashes of ultraviolet light. A phosphor coating on the inside of the tube absorbs this UV light flashes and re-emits it as visible light. The amount of mercury in a fluorescent lamp varies from 3 to 46 mg, depending on lamp size and age.

5 0
3 years ago
Other questions:
  • Eczema is a type of skin disease that appears as rashes or swelling. Eczema causes skin irritation or itchiness. What type of ti
    8·1 answer
  • What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 8.3?
    11·1 answer
  • The bond formed from electrons that are transferred is a(n) _____.
    8·1 answer
  • A mixture of gaseous reactants is put into a cylinder, where a chemical reaction turns them into gaseous products. The cylinder
    14·1 answer
  • Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: ,
    6·1 answer
  • help!! i tried answering these on my own and turning it into my teacher and she said they were all wrong , can somebody help me
    15·1 answer
  • Which of the following would have a fixed shape and volume? (3 points) nitrogen gas solid wood liquid water neon gas
    11·1 answer
  • Which state of matter has a defined volume but undefined shape
    15·2 answers
  • A mixture of Ar, He, and O2 has a total pressure of 1,015 kPa. Argon exerts a partial pressure of 152 kPa and Helium exerts a pa
    8·1 answer
  • How many neutrons does this atom have?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!