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Alecsey [184]
2 years ago
7

Please help y’all I don’t understand

Chemistry
2 answers:
Lina20 [59]2 years ago
7 0
I think it’s B



When the valence electrons form a covalent bond, they DE-LOCALIZE from their atom. They begin belonging to both atoms that form the covalent bond. ... This is in contrast with the ionic bond, where each atom gives or receives the valence electrons (which transform the atoms into ions) thus forming the ionic bond.

ycow [4]2 years ago
3 0

Answer:

Both atoms achieve a more stable configuration

Explanation:

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Hydrogen can reduce copper oxide but not aluminium oxide explain​
Llana [10]

Answer: as copper has lower electrode potential value than hydrogen, it could be reduced by hydrogen.

Explanation: hydrogen has zero reduction potential while Cu has +0.34V and Al has -1.66 V .

SO in electrochemical series who has most negative or less reduction potential value tends to be a good reducing agent than the other.

Hope it helps...

3 0
3 years ago
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Draw the Lewis dot structure for the compound gallium oxide with the chemical formula Ga2O3
Brut [27]

Answer:

Refer to your periodic table. Lewis dot structures are based off the number of valence electrons an atom has.

Looking at the compounds, we can see that Gallium has three valence electrons in its outer shell and oxygen has six. Oxygen and Gallium are going to share electrons with one another, making a V shape in their diagram.

One Oxygen would make a double bond with a Gallium, leaving one valence electron to another oxygen. That oxygen takes that Final electron. It now has 7 in its outer shell. The remaining Gallium and Oxygen do the same double bond as the one before, leaving the 7 valence electron oxygen with one more electron.

3 0
3 years ago
Given the chemical reaction Fe3O4 + H2 ⟶ Fe + H2O, identify the coefficient of H2O in the balanced equation.
Kay [80]
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5 0
3 years ago
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Hydrogen iodide is not produced by the same method is for hydrogen chloride why with reaction​
Masja [62]

Using Phosphoric acid will work perfectly for producing Hydrogen halides because its not an Oxidizing agent. ...

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H3PO4 + NaCl ==> HCl + NaH2PO4

H3PO4 + NaI ==> HI + NaH2PO4

H2SO4 + NaCl ==> HCl + NaHSO4

This method(Using H2So4) will work for all hydrogen hydrogen halide except Hydrogen Iodide and Hydrogen Bromide.

The Sulphuric acid won't be useful for producing Hydrogen Iodide because its an OXIDIZING AGENT. Whist producing the Hydrogen Iodide... Some of the Iodide ions are oxidized to Iodine.

2I-² === I2 + 2e-

5 0
3 years ago
The major products obtained from the following sequence of reactions are:
dmitriy555 [2]

Answer:

The answer is "Option C".

Explanation:

Please find the complete question and its solution in the attached file.

using Hoffman's elimination reaction.

7 0
3 years ago
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