Answer: 
Explanation:
The balanced chemical equation will be:
Here Ag undergoes oxidation by loss of electrons, thus act as anode. Nickel undergoes reduction by gain of electrons and thus act as cathode.
Where both 
are standard reduction potentials.
![E^0_{[Ag^{+}/Mg]}=+0.80V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAg%5E%7B%2B%7D%2FMg%5D%7D%3D%2B0.80V)
![E^0_{[Ni^{2+}/Ni]}=-0.25V](https://tex.z-dn.net/?f=E%5E0_%7B%5BNi%5E%7B2%2B%7D%2FNi%5D%7D%3D-0.25V)
![E^0=E^0_{[Ni^{2+}/Ni]}- E^0_{[Ag^{+}/Ag]}](https://tex.z-dn.net/?f=E%5E0%3DE%5E0_%7B%5BNi%5E%7B2%2B%7D%2FNi%5D%7D-%20E%5E0_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D)
The standard emf of a cell is related to Gibbs free energy by following relation:
= gibbs free energy
n= no of electrons gained or lost =?
F= faraday's constant
= standard emf
The Gibbs free energy is related to equilibrium constant by following relation:
R = gas constant = 8.314 J/Kmol
T = temperature in kelvin =
K = equilibrium constant
Thus the value of the equilibrium constant at 
is
Answer:
perchlorate as fuel. A possible reaction is
3Al (s) + 3NH4ClO4 (s) = Al2O3 (s) + AlCl3 (s) + 3NO (g) 6H2O (g)
Answer:
I think its a.The hockey puck loses heat molecule's.
The balanced equation for the above reaction is as follows
C₆H₁₂O₆(s) + 6O₂(g) --> 6H₂O(g) + 6CO₂<span>(g)
the limiting reactant in the equation is glucose as the whole amount of glucose is used up in the reaction.
the amount of </span>C₆H₁₂O₆ used up - 13.2 g
the number of moles reacted - 13.2 g/ 180 g/mol = 0.073 mol
stoichiometry of glucose to CO₂ - 1:6
then number of CO₂ moles are - 0.073 mol x 6 = 0.44 mol
As mentioned this reaction takes place at standard temperature and pressure conditions,
At STP 1 mol of any gas occupies 22.4 L
Therefore 0.44 mol of CO₂ occupies 22.4 L/mol x 0.44 mol = 9.8 rounded off - 10.0 L
Answer is B) 10.0 L CO₂
The nuclei of atoms become unstable when the repelling forces of the protons cannot be balanced by the number of neutrons in the nucleus. It then re-arranges itself randomly to a more stable configuration by emitting any of a series of particles. During radioactive decay, an atom does not collapse.
Since an atom is mostly empty space - that is it’s nucleus is relatively distant from the electron shells so, in the presence of extreme forces such as gravity inthe collapse of a large star, the inward pressures on the atom overcome the natural balance of the atomic structure and the ‘empty space’ disappears as nuclei are mashed together by the intense pressures and a neutron star is formed. Under even more external pressure, even the neutron star can collapse to form a black hole.
