Answer:
![f = 421.8 Hz](https://tex.z-dn.net/?f=f%20%3D%20421.8%20Hz)
Explanation:
When she moved a distance of 1 m from mid point she observe first destructive interference due to two speakers
so we can say that path difference of sound due to two speakers will be equal to half of the wavelength
so path difference is given as
![\Delta L = {3.5^2 + 12^2}^{0.5} - {1.5^2 + 12^2}^{0.5}](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%20%7B3.5%5E2%20%2B%2012%5E2%7D%5E%7B0.5%7D%20-%20%7B1.5%5E2%20%2B%2012%5E2%7D%5E%7B0.5%7D)
so it will be
![\Delta L = 12.5 - 12.093](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%2012.5%20-%2012.093)
![\Delta L = 0.4066](https://tex.z-dn.net/?f=%5CDelta%20L%20%3D%200.4066)
now we know that
![\frac{\lambda}{2} = 0.4066](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clambda%7D%7B2%7D%20%3D%200.4066)
![\lambda = 0.813](https://tex.z-dn.net/?f=%5Clambda%20%3D%200.813)
now frequency of sound is given as
![f = \frac{v}{\lambda}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7Bv%7D%7B%5Clambda%7D)
![f = \frac{343}{0.813}](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7B343%7D%7B0.813%7D)
![f = 421.8 Hz](https://tex.z-dn.net/?f=f%20%3D%20421.8%20Hz)
#1
As we are increasing the frequency in the simulation the wavelength is decreasing
So if speed remains constant then wavelength and frequency depends inversely on each other
If we are in boat and and moving over very small wavelengths then these small wavelength will be encountered continuously by the boat in short interval of times
#2
As we are changing the amplitude in the simulation there is no change in the speed frequency and wavelength.
So amplitude is independent of all these parameter
Amplitude of wave will decide the energy of wave
So light of greater intensity is the light of larger amplitude
#3
In our daily life we deal with two waves
1 sound waves
2 light waves
Explanation:
Given that,
Mass of the car, m₁ = 1250 kg
Initial speed of the car, u₁ = 7.39 m/s
Mass of the truck, m₂ = 5380 kg
It is stationary, u₂ = 0
Final speed of the truck, v₂ = 2.3 m/s
Let v₁ is the final velocity of the car. Using the conservation of momentum as :
![m_1u_1+m_2u_2=m_1v_1+m_2v_2](https://tex.z-dn.net/?f=m_1u_1%2Bm_2u_2%3Dm_1v_1%2Bm_2v_2)
![1250\times 7.39+5380\times 0=1250\times v_1+5380\times 2.3](https://tex.z-dn.net/?f=1250%5Ctimes%207.39%2B5380%5Ctimes%200%3D1250%5Ctimes%20v_1%2B5380%5Ctimes%202.3)
![v_1=-2.5\ m/s](https://tex.z-dn.net/?f=v_1%3D-2.5%5C%20m%2Fs)
So, the final velocity of the car is 2.5 m/s but in opposite direction. Hence, this is the required solution.
Answer:
<em> The elastic potential energy stored in the bungee cord = 20 J</em>
Explanation:
potential energy: This is the energy possessed by a body due to its position. The S.I unit of energy is Joules. The mathematical expression for elastic potential energy is given below
E = 1/2ke²................ Equation 1
Where E = elastic potential energy of the spring, k = force constant of the spring, e = extension
<em>Given: K = 10 N/m, e = 2.00 m</em>
<em>Substituting these values into Equation 1</em>
<em>E = 1/2(10)(2)²</em>
<em>E = 5×4</em>
<em>E = 20 Joules.</em>
<em>Therefore the elastic potential energy stored in the bungee cord = 20 J</em>
<em></em>
Answer:
ok what do you need to know about ''campaign against crime''?
Explanation: