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3 years ago

What is the best summary for this cartoon?

Physics

2 answers:

Paha777 [63]3 years ago

6 0

Answer:

C: World War I resulted from a chain reaction involving many nations.

Explanation:

Just did the questions and got it right

docker41 [41]3 years ago

3 0

Answer:

Explanation:

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13) A branch falling from a tree is to gravity as a car driving on the road is to A) a driver's foot off of the accelerator, coa

IgorC [24]

<span>a driver's foot off the accelerator and on the break pedal. C</span>

3 0

2 years ago

Read 2 more answers

To determine the pressure in a fluid at a given depth with the air-filled cartesian diver, we can employ Boyle's law, which stat

aniked [119]

Answer:

The pressure at this depth is $1.235\cdot P_{atm}$ .

Explanation:

According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:

$\frac{P_{2}}{P_{1}} = \frac{V_{1}}{V_{2}}$ (1)

Where:

$V_{1}, V_{2}$ - Initial and final volume.

$P_{1}, P_{2}$ - Initial and final pressure.

If we know that $V_{2} = 0.81\cdot V_{1}$ , then the pressure ratio is:

$\frac{P_{2}}{P_{1}} = 1.235$

If $P_{1} = P_{atm}$ , then the final pressure of the gas is:

$P_{2} = 1.235\cdot P_{atm}$

The pressure at this depth is $1.235\cdot P_{atm}$ .

6 0

3 years ago

A textbook of mass 2.10 kg rests on a frictionless, horizontal surface. A cord attached to the book passes over a pulley whose d

Lilit [14]

Answer:

the tension in the part of the cord attached to the textbook is 7.4989 N

Explanation:

Given the data in the question;

As illustrated in the image below;

first we determine the value of the acceleration,

along vertical direction; we use the second equation of motion;

y = ut + $\frac{1}{2}$ a $_y$ t²

we substitute;

0 m/s for u, 1.29 m for y, 0.850 s for t,

1.29 = 0×0.850 + $\frac{1}{2}$ ×a $_y$ ×(0.850)²

1.29 = 0.36125a $_y$

a $_y$ = 1.29 / 0.36125

a $_y$ = 3.5709 m/s²

Now when the text book is moving with acceleration , the dynamic equation will be;

T₁ = m₁a $_y$

where m₁ is the mass of the text book ( 2.10 kg )

a $_y$ is the vertical acceleration ( 3.5709 m/s² )

so we substitute

T₁ = 2.10 × 3.5709

T₁ = 7.4989 N

Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N

3 0

2 years ago

If a certain brand of solar panels is rated at a value of 1.50 KW/m2 , and a person needed to generate 2.50 MJ in an hour, what

alisha [4.7K]

Answer:

$A=0.462\ m^2$

Explanation:

Power rating of a solar panel is 1.50 KW/m²

It generates 2.50 MJ in an hour.

We need to find the area of this type of solar panel would be needed. The power pertaining to generate this energy is given by :

$P=\dfrac{2.5\times 10^6}{1\ h}\\\\P=\dfrac{2.5\times 10^6}{3600\ s}\\\\P=694.44\ W$

Let A be the area of the solar panel. It is calculated as follows :

$\dfrac{P}{A}=1.5\times 10^3\\\\A=\dfrac{694.44}{1.5\times 10^3}\\A=0.462\ m^2$

So, the required area of the solar panel is $0.462\ m^2$ .

4 0

2 years ago

The wavelength of light changes as light goes from one medium to another, while the frequency remains the same. Is the wavelengt

Verizon [17]

Answer:

λw = 450 nm

λg = 402 nm

Explanation:

Frequency of a wave is defined as the number of vibrations coming out of the source in one second.

The frequency of a wave is the fundamental property of the source.

The relation among the wavelength, wave velocity and frequency is given by

wave velocity = frequency x wavelength

Frequency is constant while the velocity and wavelength changes.

wavelength in air, λa = 600 nm

Let the wavelength in water is λw.

speed of light in air, c = 3 x 10^8 m/s

speed of light in water = 75 % of c = 0.75 x 3 x 10^8 = 2.25 x 10^8 m/s

speed of light in plexglass = 67 % of c = 0.67 x 3 x 10^8 = 2.01 x 10^8 m/s

$\frac{\lambda _{w}}{\lambda _{a}}=\frac{velocity in water}{velocity in light }$

$\lambda _{w}=600\times \frac{2.25\times 10^{8}}{3\times 10^{8}}$

λw = 450 nm

$\frac{\lambda _{g}}{\lambda _{a}}=\frac{velocity in glass}{velocity in light }$

$\lambda _{g}=600\times \frac{2.01\times 10^{8}}{3\times 10^{8}}$

λg = 402 nm

6 0

3 years ago