All categories

2 years ago

What tool would you use to separate nails from gravel

Physics

2 answers:

Minchanka [31]2 years ago

7 0

It would be a wire mesh

nekit [7.7K]2 years ago

3 0

I think a magnet would be best. It's cheap, quick and easy,
and very technical, so that's the one I would use.

You might be interested in

A 2-kg toy car accelerates from 0 to 5 m/s2. It

yan [13]

10 joules of work is done by the object

8 0

2 years ago

What are symptoms of Gomorrah

marishachu [46]

Consumed by Fire and Brimstone would be 1 symptom of Gomorrah lol

5 0

2 years ago

Jupiter's satellite Europa orbits Jupiter with a period of 3.55 d at an orbital radius of 6.71 108 m (assume the orbit to be cir

yawa3891 [41]

Answer:

(a)

M = 1.898 x 10^27 kg

(b)

v = 13.74 km/s

Explanation:

Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s

Radius, r = 6.71 x 10^8 m

G = 6.67 x 10^-11 Nm^2/kg^2

(a) $T=2\pi \sqrt{\frac{r^{3}}{GM}}$

$M=\frac{4\pi ^{2}r^{3}}{GT^{2}}$

$M=\frac{4\times3.14^{2}\times 6.71^{3}\times 10^{24}}{6.67\times 10^{-11}\times 306720^{2}}$

M = 1.898 x 10^27 kg

(b) Let v be the orbital velocity

$v=\frac{2\pi r}{T}$

$v=\frac{2\times 3.14\times 6.71\times 10^{8}}{306720}$

v = 13739.5 m/s

v = 13.74 km/s

(b) The gravitational field E is given by

$E = \frac{GM}{r^{2}}$

$E = \frac{6.67\times10^{-11}\times 1.898\times 10^{27}}{6.71^{2}\times 10^{16}}$

E = 0.28 N/kg

6 0

2 years ago

A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 43 kg barbell straight up fro

Tasya [4]

Answer:

A. 231.77 J

B. 5330.71 J

C. 46 donuts

Explanation:

A. To lift the barbell once, she will have to extend it the full length of her arm. The work done will then be:

W = F * d

Where the force is the weight of the barbell.

F = m * g

Hence, the work done in lifting the barbell is:

W = m * g * d

W = 43 * 9.8 * 0.55

W = 231.77 J

B. If she does 23 repetitions, the total energy she expend will be equal to the Potential energy when the barbell is lifted multiplied by 23:

E = 23 * m * g * d

E = 23 * 231.77

E = 5330.71 J

C. 1 Joule = 4.184 calories

5330.71 Joules = 5330.71 * 4.184 = 22303.69

If 1 donut contains 490 calories, the number of donuts she will need will be:

N = 22303.69/490 = 45.5 donuts or 46 donuts

5 0

3 years ago

Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq

Ulleksa [173]

The charge on each the balloon is 100nC or 1.2 × 10^-7 C

Consider two balloons of diameter 0.200m each with a mass of 1.00g hanging apart with 0.0500m separation on the ends of string making angles of 10.0° with the vertical.

The charge on each balloon can be found from

$F_{e} = \frac{k_{e}q^{2} }{r^{2}} \\q = \sqrt{\frac{k_{e}q^{2} }{r^{2}}} \\\\q = \sqrt{\frac{(2\times10^{-3N}(0.25m)^{2}}{8.99\times10^{9}N\cdotm^{2}/C^{2}}\\$

$q = 1.2\times10^{-7}C$ or 100nC

An electric charge is the property of matter where it has more or fewer electrons than protons in its atoms. Electrons carry a negative charge and protons carry a positive charge. The matter is positively charged if it contains more protons than electrons and negatively charged if it contains more electrons than protons.

Learn more about the charge here:

brainly.com/question/14713274

#SPJ4

3 0

1 year ago