A car is traveling up a hill that is inclined at an angle θ above the horizontal. Determine the ratio of the magnitude of the no
1 answer:
Explanation:
The weight of the car is equal to, ...........(1)
Where
m is the mass of car
g is the acceleration due to gravity
The normal or vertical component of the force is,
or
.............(2)
The horizontal component of the force is,
Taking ratio of equation (1) and (2) as :
or
Hence, this is the required solution.
You might be interested in
Answer:
a) b) d)
Explanation:
The question is incomplete. The Complete question might be
In an inertial frame of reference, a series of experiments is conducted. In each experiment, two or three forces are applied to an object. The magnitudes of these forces are given. No other forces are acting on the object. In which cases may the object possibly remain at rest? The forces applied are as follows: Check all that apply.
a)2 N; 2 N
b) 200 N; 200 N
c) 200 N; 201 N
d) 2 N; 2 N; 4 N
e) 2 N; 2 N; 2 N
f) 2 N; 2 N; 3 N
g) 2 N; 2 N; 5 N
h ) 200 N; 200 N; 5 N
For th object to remain at rest, sum of all forces must be equal to zero. Use minus sign to show opposing forces
a) 2+(-2)=0 here minus sign is to show the opposing firection of force
b) 200+(-200)=0
c) 200+(-201)0
d) 2+2+(-4)=0
e) 2+2+(-2)0
f) 2+2+(-3) 0; 2+(-2)+3
0
g) 2+2+(-5)0; 2+(-2)+5
0
h)200 + 200 +(-5)0; 200+(-200)+5
0
Answer:
distance = 21.56 m
Explanation:
given data
mass = 50 kg
initial velocity = 18.2 m/s
force = -200 N ( here force applied to opposite direction )
final velocity = 12.6 m/s
solution
we know here acceleration will be as
acceleration a = force ÷ mass
a = = -4 m/s²
we get here now required time that is
required time = ...............1
put here value
required time =
so distance will be
distance = ........2
distance =
distance = 21.56 m